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Assigning a value to a vector in a for loop

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Kim
Kim el 14 de Sept. de 2014
Comentada: Star Strider el 14 de Sept. de 2014
I'm trying to assign individual times to a vector 'toa' in a loop using:
for jj = 1:nvar
ktau = jj * tau0;
toa(jj) = jj * tau0;
{buncha calcs}
end
I use ktau in following equations, and I want to keep a vector of all the times used.
When I try to run the function I get: In an assignment A(I) = B, the number of elements in B and I must be the same.
Error in alvarQ (line 115) toa(jj) = jj.*tau0; % this was time calc above
Why is that? Shouldn't that work?
Thanks, Kim

Respuestas (3)

Image Analyst
Image Analyst el 14 de Sept. de 2014
Evidently tau0 is a vector, not a scalar, so the product of jj*tau0 is also a vector. You can't stuff a vector of multiple elements into a single element of toa. Maybe you meant tau0(jj)???? What does "whos ktau" show?

Star Strider
Star Strider el 14 de Sept. de 2014
Is ‘tau0’ a vector or a scalar?
Otherwise, your ‘{buncha calcs}’ could be the problem. Are you doing anything to ‘toa’ or ‘tau0’ in them?

Kim
Kim el 14 de Sept. de 2014
Y'all, thanks for the help. Based on what you said I went and looked at tau0. It was supposed to be a scalar. I'd read it out of a file header. However it was stored as text i.e. '9.9998e-6' instead of 9.9998e-6.
Quick use of str2num straightened me out, and things ran fine.

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