Equivalent of numpy.where() value choice parameters
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Andrew Glick
el 10 de Oct. de 2021
Comentada: Jan
el 13 de Oct. de 2021
I am trying to emulate the behavior of the Numpy function numpy.where() in MATLAB, specifically the optional 2 parameters that allow picking from from other arrays.
I have the following Python code which selects
>>> import numpy as np
>>> x = np.arange(10)
>>> y = np.arange(10) * -0.1
>>> z = np.where(x % 2 == 0, x, y)
>>> print(z)
[ 0. -0.1 2. -0.3 4. -0.5 6. -0.7 8. -0.9]
The function numpy.where() selects between the two arrays, x and y, based on the condition in the first argument.
The best I have been able to do in MATLAB is:
x = 0:9
y = (0:9) * -0.1
z = zeros(size(x))
z(mod(x, 2)!=0) = y(mod(x,2)==0)
z(mod(x, 2)~=0) = y(mod(x,2)~=0)
Is there a better way of doing this?
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Jan
el 10 de Oct. de 2021
Your code looks almost fine:
x = 0:9
y = (0:9) * -0.1
z = zeros(size(x));
z(mod(x, 2) == 0) = x(mod(x,2) == 0);
% ^ not ! ^ not y
z(mod(x, 2) ~= 0) = y(mod(x,2) ~= 0);
More efficient:
z = x;
m = (mod(x, 2) ~= 0);
z(m) = y(m);
2 comentarios
Jan
el 13 de Oct. de 2021
Typos are then beloved companion of the programmer. They emerge from expressing thoughts by fingers. As soon as we omit the keyboards by developping a mind controlled input method, the new device will get a bi-directional interface and monopolistic internet services will project commercials directly in my subconciousness. Therefore I like typos.
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