I tried the suggestion in this thread but seems to work only for double
Table Find Duplicate Rows (double, char, datetime)
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Hello, in table A with 100,000 rows and 40 columns, is there a way to find duplicate rows?
The elements are of the type: double, char, datetime
Thanks
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the cyclist
el 25 de Oct. de 2021
You might need to share some more details about your table, but you should be able to use the unique function.
% Make some pretend data, which is 8 rows with 4 unique ones
tbl = array2table([magic(4); magic(4)]);
% Find the unique rows, along with indices for identifying the duplicates
[uniqueTableRows,indexToUniqueRows,indexBackFromUnique] = unique(tbl);
See the documentation for details on the indices that are reported.
2 comentarios
the cyclist
el 26 de Oct. de 2021
Editada: the cyclist
el 26 de Oct. de 2021
Different data types should not be a problem with this method:
% Make some pretend data of different types
n = [1; 2; 1; 1; 2; 1];
c = {'a';'b';'a';'b';'a';'b'};
t = datetime({'2014-05-26';'2014-08-03';'2014-05-26';'2014-08-03';'2014-05-26';'2014-08-03'},'InputFormat','yyyy-MM-dd');
% Put them in a table
tbl = table(n,c,t)
% Find the unique rows, along with indices for identifying the duplicates
[uniqueTableRows,indexToUniqueRows,indexBackFromUnique] = unique(tbl)
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