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char array to cell array convert?

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Divyesh pandav
Divyesh pandav el 27 de Oct. de 2021
Comentada: Divyesh pandav el 30 de Oct. de 2021
T cell array
T = {[5.8882656], [0.01232356], [0.02556545],[0.035659595] , ...}
A = num2str(T,'%.2f');
A = '5.88 0.01 0.02 0.03 0.04 0.05'
A = str2num(A)
A = NaN
OUTPUT I WANT
A = { 5.88] ,[0.01],[0.02],[0.03],[0.04] , [0.05] }
  2 comentarios
Johan
Johan el 27 de Oct. de 2021
T = {[5.8882656], [0.01232356], [0.02556545],[0.035659595]}
T = 1×4 cell array
{[5.8883]} {[0.0123]} {[0.0256]} {[0.0357]}
A = cellfun(@(x) str2num(num2str(x,'%.2f')), T)
A = 1×4
5.8900 0.0100 0.0300 0.0400
Rik
Rik el 27 de Oct. de 2021
@Johan Pelloux-Prayer This looks like an answer. Please move it to the answer section.
A few notes: using cellfun is simply hiding the for loop (which is generally faster). You are also using str2num instead of str2double. str2num calls eval internally and can do a lot of damage if used with untrusted input. str2double has as downside that it will only works on scalars, but is otherwise completely safe to use (it will return NaN if it fails).

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Rik
Rik el 27 de Oct. de 2021
If you want to round your data, just use round:
T = {[5.8882656], [0.01232356], [0.02556545],[0.035659595]};
T = cell2mat(T);
T = round(T,2);
T = num2cell(T)
T = 1×4 cell array
{[5.8900]} {[0.0100]} {[0.0300]} {[0.0400]}
You can ignore the trailing zeros when this data is displayed. You should distinguish the data itself and the way it is displayed in Matlab.
  3 comentarios
Rik
Rik el 27 de Oct. de 2021
What I mean by that is that it looks as if the numbers have 4 decimals, while we just rounded them to 2. The reality is that we rounded the values to the closest equivalent that can be represented in the internal binary storage system that Matlab uses.
When you see the output in the command window (or here just below the code), that internal representation is translated to a human readable form again.
Divyesh pandav
Divyesh pandav el 30 de Oct. de 2021
@Rik Got it..!!
Thank you

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