why in this function they use empty square brackets?
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Almog Na
el 13 de Nov. de 2021
Comentada: Almog Na
el 14 de Nov. de 2021
and how exactly this is solving the determinant, I don't completley understand what they did here/
sorry if it's a dumb question I'm new to coding and to matlab.
function det = myDet(A)
if isscalar(A)
det = A;
return
end
det = 0;
top_row = A(1,:);
A(1,:) = [];
for i = 1:size(A,2) % number of columns
A_i = A;
A_i(:,i) = [];
det = det+(-1)^(i+1)*top_row(i)*myDet(A_i);
end
end
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John D'Errico
el 13 de Nov. de 2021
Editada: John D'Errico
el 13 de Nov. de 2021
It is not a dumb question at all, because the syntax used by MATLAB to delete a row or column of an array may not be obvious. But the best way, as others have said, is to try it out. See what happens to the array when you do that. Getting your hands dirty is the best way to learn.
A = magic(3)
% first, I'll delete the second row of A
A(2,:) = []
% Next, delete the third column of that matrix.
A(:,3) = []
Más respuestas (2)
Cris LaPierre
el 13 de Nov. de 2021
In this context, it appears to be deleting elements from A.
Try it out in MATLAB to see what it is doing.
A = rand(3)
A(1,:)=[]
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