how to xor binary vector in matrix
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Respuesta aceptada
Roger Stafford
el 18 de Oct. de 2014
If I understand what you want and if the rows have a multiple of three elements, this should work for you:
X = xor(xor(M(:,1:3:end-2),M(:,2:3:end-1)),M(:,3:3:end));
If this is not what you want, you should clarify that phrase "every three bits together" so that it is clearly understood. As it stands, it is easily misunderstood. It should be simple to make it clear what you mean if you carefully construct a good, meaningful example.
4 comentarios
Roger Stafford
el 18 de Oct. de 2014
When you used the word 'last' I thought you wanted the extra zeros appended to the right end. Apparently you want them appended to the left end. If that is the case, just reverse the order:
[m,n] = size(M);
M2 = [zeros(m,3*ceil(n/3)-n),M];
X = xor(xor(M2(:,1:3:end-2),M2(:,2:3:end-1)),M2(:,3:3:end));
Más respuestas (0)
Ver también
Categorías
Más información sobre Cell Arrays en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!