Using a print statement in a loop
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Hey guys, I'm having some trouble with running an fprintf statement in a loop. What I did is created a character array, and I want to run a loop to print the values of another matrix with the labels from that character array. Here's my code:
x = (pi/4);
M = [-1 0 0 0 0 0 0 0;
0 0 0 0 -1 0 0 0;
1 0 cos(x) 0 0 0 0 0;
0 -1 -sin(x) 0 0 0 0 0;
0 0 0 1 0 0 0 0;
0 1 0 0 0 1 0 0;
0 0 -sin(x) -1 0 0 0 1;
0 0 cos(x) 0 1 0 1 0];
E = [1000 0 0 500 -500 0 0 0]';
f1 = M\E;
F = char(['F1'; 'F2'; 'F3'; 'F4'; 'F5'; 'R1'; 'R2'; 'R3']);
for x = x
fprintf('%.3f = %.3f Newtons \n\n', F, f1)
end
My result is something really strange, and I don't understand why it is what it is:
70.000 = 70.000 Newtons
70.000 = 70.000 Newtons
70.000 = 82.000 Newtons
82.000 = 82.000 Newtons
49.000 = 50.000 Newtons
51.000 = 52.000 Newtons
53.000 = 49.000 Newtons
50.000 = 51.000 Newtons
-1000.000 = -1500.000 Newtons
1414.214 = -500.000 Newtons
0.000 = 1500.000 Newtons
-1000.000 = 500.000 Newtons
What I WANT to do is have each label of F pair up with its respective value from f1. I have NO idea why it's printing numerical values for what should be a character string.
Anyway, thanks in advance!
0 comentarios
Respuestas (2)
Image Analyst
el 18 de Oct. de 2014
F is a string, so use %s instead of %f:
fprintf('%s = %.3f Newtons \n\n', F, f1)
2 comentarios
Image Analyst
el 18 de Oct. de 2014
Your loop iterator, x, was wrong, and you need to index F and f1. Try this:
x = (pi/4);
M = [-1 0 0 0 0 0 0 0;
0 0 0 0 -1 0 0 0;
1 0 cos(x) 0 0 0 0 0;
0 -1 -sin(x) 0 0 0 0 0;
0 0 0 1 0 0 0 0;
0 1 0 0 0 1 0 0;
0 0 -sin(x) -1 0 0 0 1;
0 0 cos(x) 0 1 0 1 0]
E = [1000 0 0 500 -500 0 0 0]'
f1 = M\E
F = char(['F1'; 'F2'; 'F3'; 'F4'; 'F5'; 'R1'; 'R2'; 'R3'])
for row = 1:length(f1)
fprintf('%s = %.3f Newtons \n\n', F(row,:), f1(row))
end
Roja G
el 29 de Jul. de 2020
%%%LEACH%%
clear ;
%%%%%%%%%%%%%%%%%%%% PARAMETERS %%%%%%%%%%%%%%
% Field Dimensions - x and y maximum (in meters)
xm=100;
ym=100;
% x and y coordinates of the sink
% placing the sink at centre of the field
sink.x=0.5*xm;
sink.y=0.5*ym;
% Number of nodes in the field
n=100;
% Optimal election probability of a node to be come cluster head
p=0.1;
% Energy model (ALL VALUES IN JOULES)
% Intial Energy(same for all nodes - homogeneous scenario)
Eo=0.5;
% Eelec=Etx=Erc
ETX=50*0.000000001; % transmission power
ERX=50*0.000000001;
% Transmit amplifier types
Efs=10*0.00000000001;
Emp=0.0013*0.00000000001;
% Data aggreagation energy
EDA=5*0.000000001;
% Values for Hetereogeneity
% Percentage of nodes than are advanced
m=0.1;
% \alpha
a=1;
% maximum number of rounds
rmax=4000;
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%END OF PARAMETERS%%%%%%%%%%%%%%%%%
% Computaion of do
do=sqrt(Efs/Emp); % approx. value of do = 84.73
% Creation of the random sensor network
figure(1);
for i=1:1:n
% whenever we perform node deployment, we need to create a data type for sensor node in Matlab, since a node can have many attributes
% here S is the data type of our sensor node
S(i).xd=rand(1,1)*xm; % xd represents x-coordinate of node generated randomly
XR(i)=S(i).xd; % sequential indexing of node
S(i).yd=rand(1,1)*ym; % yd represents y-coordinate of node generated randomly
YR(i)=S(i).yd; % sequential indexing of node
S(i).G=0; % shows whether the node belongs to any group or not, here it doesnt belong to any group so 0
%intially there are no cluster heads only nodes
S(i).type='N'; % states that it is just a node, not a cluster head
temp_rnd0=i;
%Random election of normal nodes
if(temp_rnd0>=m*n+1)
S(i).E=Eo; % initial energy of the node is Eo
S(i).ENERGY=0;
plot(S(i).xd,S(i).yd,'o');
hold on; % cause we are plotting multiple nodes in a single figure
end
%Random election of advanced nodes
if(temp_rnd0<m*n+1)
S(i).E=Eo;
S(i).ENERGY=1;
plot(S(i).xd,S(i).yd,'+');
hold on;
end
end
S(n+1).xd=sink.x; % x-coordinate of sink
S(n+1).yd=sink.y; % y-coordinate of sink
plot(S(n+1).xd,S(n+1).yd,'x');
%First Iteration
figure(1);
%counter for CHs
countCHs=0;
%counter for CHs per round
rcountCHs=0;
cluster=1; % initializing clusters
countCHs;
rcountCHs=rcountCHs+countCHs;
flag_first_dead=0;
for r=0:1:rmax % max number of rounds
r;
% Operation for epoch i.e., how the cluster head is getting selected
% after initializing epoch, the selection procedure starts
if(mod(r, round(1/p) )==0)
for i=1:1:n
S(i).G=0;
S(i).c1=0;
end
end
hold off;
% Number of dead nodes
dead=0;
% Number of dead Advanced Nodes
dead_a=0;
% Number of dead Normal Nodes
dead_n=0;
% counter for bit transmitted to base station and to cluster head
packet_TO_BS=0;
packet_TO_CH=0;
% counter for bit transmitted to base station and to cluster head per round
PACKET_TO_CH(r+1)=0;
PACKET_TO_BS(r+1)=0;
figure(1);
for i=1:1:n
% checking if there is a dead node
if(S(i).E<=0)
plot(S(i).xd,S(i).yd,'red .');
%plot(S(i).xd,S(i).yd,'red .');
dead=dead+1;
if(S(i).ENERGY==1)
dead_a=dead_a+1;
end
if(S(i).ENERGY==0)
dead_n=dead_n+1;
end
hold on;
end
if S(i).E>0
S(i).type='N';
if (S(i).ENERGY==0)
plot(S(i).xd,S(i).yd,'o');
end
if (S(i).ENERGY==1)
plot(S(i).xd,S(i).yd,'+');
end
hold on;
end
totalenergy(i)=S(i).E;
% if r+1==1095
% S(i).E=0;
% end
end
total_energy=sum(totalenergy);
plot(S(n+1).xd,S(n+1).yd,'+');
STATISTICS(r+1).DEAD = dead;
DEAD(r+1) = dead;
if r+1==1095
S(i).E=0;
end
% When the first node dies
if(dead==1)
if(flag_first_dead==0)
first_dead=r;
flag_first_dead=1;
end
end
countCHs=0;
cluster=1;
for i=1:1:n
if(S(i).E>0)
temp_rand=rand;
if ( (S(i).G)<=0)
% Election of cluster heads
if(temp_rand<=(p/(1-p*mod(r,round(1/p))))*(S(i).E/total_energy)) % *(S(i).E/total_energy) is the modified leach formula, which represents residual energy of the node by the total energy of the network
countCHs=countCHs+1;
PACKET_TO_BS(r+1)=packet_TO_BS;
S(i).type='C';
S(i).G=round(1/p)-1;
C(cluster).xd=S(i).xd;
C(cluster).yd=S(i).yd;
plot(S(i).xd,S(i).yd,'k*');
distance=sqrt( (S(i).xd-(S(n+1).xd) )^2+ (S(i).yd-(S(n+1).yd) )^2 ); % distance formula
% corresponding distance from base station follows 2 types of routing based on whether d is < or > do (declared at start of the code)
C(cluster).distance=distance;
C(cluster).id=i;
X(cluster)=S(i).xd;
Y(cluster)=S(i).yd;
cluster=cluster+1;
%Calculation of Energy dissipated
distance;
if(distance>do) % multipath routing, current energy of the node = S(i).E, energy dissipation = (ETX+EDA)*(4000) + Emp*4000*(distance*distance*distance*distance)
S(i).E = S(i).E - ((ETX+EDA)*(4000) +Emp*4000*(distance*distance*distance*distance)); % packet size = 4000, Emp - multipath routing coefficient
end
if(distance<=do) % free space routing, energy dissipation = (ETX+EDA)*(4000) +Efs*4000*(distance*distance)
S(i).E = S(i).E - ((ETX+EDA)*(4000) +Efs*4000*(distance*distance)); % free space routing coefficient
end
end
end
end
end
STATISTICS(r+1).CLUSTERHEADS=cluster-1;
CLUSTERHS(r+1)=cluster-1;
% Election of associated cluster head for normal nodes
% calculating distance from cluster head to member nodes, if nearby then cluster member
for i=1:1:n
if (S(i).type == 'N' && S(i).E>0)
if(cluster-1>=1)
min_dis=sqrt( (S(i).xd-S(n+1).xd)^2 + (S(i).yd-S(n+1).yd)^2);
min_dis_cluster=1;
for c=1:1:cluster-1
temp=min(min_dis, sqrt ( (S(i).xd-C(c).xd)^2 + (S(i).yd-C(c).yd)^2));
if( temp<min_dis )
min_dis=temp;
min_dis_cluster=c;
end
end
% Energy dissipated by associated cluster head (same as above)
min_dis;
if (min_dis>do)
S(i).E=S(i).E- (ETX*(4000) + Emp*4000*( min_dis * min_dis * min_dis * min_dis));
end
if (min_dis<=do)
S(i).E=S(i).E- (ETX*(4000) + Efs*4000*( min_dis * min_dis)); % energy dissipated while receiving the information from the nodes
end
%Energy dissipated
if(min_dis>0)
S(C(min_dis_cluster).id).E = S(C(min_dis_cluster).id).E - ( (ERX+EDA)*4000); % ERX+EDA)*4000 - energy dissipated by receiving power of each and every cluster head
PACKETS_TO_CH(r+1)=n-dead-cluster+1;
end
S(i).min_dis=min_dis;
S(i).min_dis_cluster=min_dis_cluster;
end
end
end
hold on;
countCHs;
rcountCHs=rcountCHs+countCHs;
end
AlliveLeach = 100 - DEAD; % after total energy is dissipated, nodes start becoming dead one after the other
% this is the criterion (performance of alive nodes) for analyzing the network lifetime
%plot (1:4001,AlliveLeach,'-r') % can be upto 40001 rounds
2 comentarios
Roja G
el 29 de Jul. de 2020
could you please help me.. i want to print a statement to find the cluster head formation and residual energy for each round . how to use the for loop to the above code
Image Analyst
el 29 de Jul. de 2020
This is not an answer to Luke's question.
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