1-hour offset in time string conversion
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Hi there, I'm having trouble in converting string to datenum values. Somehow, there will be an offset of one hour when converting back to datestr. So, here is my example:
>> timestr = '1986-03-13T11:59:58.000Z';
>> test = datenum(timestr,'yyyy-mm-ddTHH:MM:SS.000Z')
test =
7.2544e+05
>> datestr(test,'yyyy-mm-ddTHH:MM:SS')
ans =
1986-03-13T12:59:58
To me, this seems pretty weird. I might be missing something very simple, though. I'd be glad if any of you could help me! Thanks
Dennis
1 comentario
Star Strider
el 24 de Oct. de 2014
I suggest you report this as a bug, specifically because in R2014b I get an even weirder result from running your code:
1986-03-13T04:59:58
a -19 hour error!
Respuesta aceptada
Más respuestas (1)
Dennis
el 3 de Nov. de 2014
0 votos
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Más información sobre Dates and Time en Centro de ayuda y File Exchange.
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