loop calculation and skipping the numbers

6 Dic. 2021
1 Respuesta
Respuesta aceptada
Actualizado a las 8 Dic. 2021
3 Visualizaciones (30 días)
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d=20;
h=2;
g=9.8;
u=zeros(1)
u = 0
v=zeros(1)
v = 0
for x=[1 6 11 16 21 ]
for t=[1 6 11 16 21 26 31]
u(x,t)=h*sqrt(g/d)*(sech((sqrt(3*h/4*d^3))*(((x-1)/10)-(sqrt(g/d)*(1+(h/2*d))*((t-1)/10)))))^2;
v(x,t)=h*(sech((sqrt(3*h/4*d^3))*((x-1/10)-(sqrt(g/d)*(1+(h/2*d))*(t-1/10)))))^2;
end
end
disp(u)
Columns 1 through 22 1.4000 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.0000 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.0000 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.0000 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.0000 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Columns 23 through 31 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
disp(v)
1.0e-220 * Columns 1 through 22 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.1605 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.0000 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Columns 23 through 31 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
I use this code to evaluate the value of u and v at different x and t .I want to skip the values so i wish this code .But all the values are not displayed.

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 Respuesta aceptada

Star Strider
Star Strider el 6 de Dic. de 2021
Ran in:

0 votos

Ran in:
The indexing is incorrect. It leaves gaps. The gaps can be eliminated with a more efficient indexing approach.
This fixes that problem, however other problems may remain.
d=20;
h=2;
g=9.8;
% u=zeros(1)
% v=zeros(1)
xv=[1 6 11 16 21 ];
tv=[1 6 11 16 21 26 31];
u = NaN(numel(xv), numel(tv));
v = NaN(numel(xv), numel(tv));
for k1 = 1:numel(xv)
x = xv(k1);
for k2 = 1:numel(tv)
t = tv(k2);
u(k1,k2)=h*sqrt(g/d)*(sech((sqrt(3*h/4*d^3))*(((x-1)/10)-(sqrt(g/d)*(1+(h/2*d))*((t-1)/10)))))^2;
v(k1,k2)=h*(sech((sqrt(3*h/4*d^3))*((x-1/10)-(sqrt(g/d)*(1+(h/2*d))*(t-1/10)))))^2;
end
end
disp(u)
1.4000 0 0 0 0 0 0 0.0000 0 0 0 0 0 0 0.0000 0 0 0 0 0 0 0.0000 0 0 0 0 0 0 0.0000 0 0 0 0 0 0
disp(v)
1.0e-220 * 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.1605 0 0 0 0 0 0 0.0000 0 0 0 0 0 0 0 0 0 0 0 0 0
.

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YOGESHWARI PATEL
YOGESHWARI PATEL el 8 de Dic. de 2021
u = NaN(numel(xv), numel(tv));
v = NaN(numel(xv), numel(tv));
for k1 = 1:numel(xv)
x = xv(k1);
for k2 = 1:numel(tv)
can you exaplain the above four lines
Star Strider
Star Strider el 8 de Dic. de 2021
Preallocating the matrices, then referencing the variables as elements of the original variable vectors.

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Preguntada:

YOGESHWARI PATEL
YOGESHWARI PATEL
el 6 de Dic. de 2021

Comentada:

Star Strider
Star Strider
el 8 de Dic. de 2021

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