Hello,
I would like to plot the Bode diagram of the following transfer function:
If I use the following code, I do not get appropriate results:
s = tf('s');
f1 = 0.99 * 18.88;
f2 = (1 + s / (2 * 3.1415 * 10.58)) / (1 + s / (s / (2 * 3.1415 * 26.74)));
f3 = (s / (2 * 3.1415 * 23.17)) / (1 + s / (2 * 3.1415 * 23.17));
f4 = (s / (2 * 3.1415 * 25.21)) / (1 + s / (2 * 3.1415 * 25.21));
f5 = 1 / (1 + s / (2 * 3.1415 * 48000));
bode(f1 * f2 * f3 * f4 * f5); grid on;
However, if I only plot one factor of the transfer function, it seems to work properly.
I would really appreaciate any help regarding this problem.

4 comentarios

s = tf('s');
f1 = 0.99 * 18.88;
f2 = (1 + s / (2 * 3.1415 * 10.58)) / (1 + s / (s / (2 * 3.1415 * 26.74)));
f3 = (s / (2 * 3.1415 * 23.17)) / (1 + s / (2 * 3.1415 * 23.17));
f4 = (s / (2 * 3.1415 * 25.21)) / (1 + s / (2 * 3.1415 * 25.21));
f5 = 1 / (1 + s / (2 * 3.1415 * 48000));
bode(f1 * f2 * f3 * f4 * f5); grid on;
What is your concern with the Bode plot?
Pascal Warten
Pascal Warten el 18 de Dic. de 2021
This is not the Bode plot of the given transfer function. The last factor of the transfer function models a lowpass filter which cannot be seen in the Bode plot.
The amplitude frequency response should roughly look like this:
Most impportantly, correct the typo in f2 as indicated below by @Star Strider.
Also, bode() always works with frequencies in rad/TimeUnit. If you want to specify the frequency in Hz, you can do it manually.
s = tf('s');
f1 = 0.99 * 18.88;
f2 = (1 + s / (2 * 3.1415 * 10.58)) / (1 + s / (2 * 3.1415 * 26.74));
f3 = (s / (2 * 3.1415 * 23.17)) / (1 + s / (2 * 3.1415 * 23.17));
f4 = (s / (2 * 3.1415 * 25.21)) / (1 + s / (2 * 3.1415 * 25.21));
f5 = 1 / (1 + s / (2 * 3.1415 * 48000));
whz = logspace(0,6);
[m,p] = bode(f1 * f2 * f3 * f4 * f5,2*pi*whz);
semilogx(whz,db(squeeze(m)))
Or use bodeplot() to plot in Hz directly
opts = bodeoptions;
opts.FreqUnits = 'Hz';
bodeplot(f1*f2*f3*f4*f5,opts);
Pascal Warten
Pascal Warten el 20 de Dic. de 2021
Thank you for your tips regarding the specifications of the units.

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 Respuesta aceptada

Star Strider
Star Strider el 18 de Dic. de 2021
There is a typographical error in ‘f2’ and correcting it produces the desired result —
s = tf('s');
f1 = 0.99 * 18.88;
f2 = (1 + s / (10.58)) / (1 + s / (26.74));
f3 = (s / (23.17)) / (1 + s / (23.17));
f4 = (s / (25.21)) / (1 + s / (25.21));
f5 = 1 / (1 + s / (48000));
figure
bode(f1 * f2 * f3 * f4 * f5, {0 5E+7*2*pi})
grid on;
.

2 comentarios

Pascal Warten
Pascal Warten el 20 de Dic. de 2021
Thanks a lot!
Star Strider
Star Strider el 20 de Dic. de 2021
As always, my pleasure!
.

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