I am a beginner-level programmer. Kindly help me to count the number of images from multiple folders at once
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    Akhil Narayanan
 el 11 de En. de 2022
  
    
    
    
    
    Editada: Image Analyst
      
      
 el 11 de En. de 2022
            All the folders in the below path contains images. I want to count number of images in each folder and need to get the output in .csv format. 

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  Walter Roberson
      
      
 el 11 de En. de 2022
        dinfo = dir(fullfile('*', '*.jpg'));
folders = {dinfo.folder};
[~, basefolder] = fileparts(folders);
[G, folder_name] = findgroups(basefolder);
image_count = accumarray(G(:), 1);
results = table(folder_name, image_count);
writetable(results, 'OutputFileName.csv');
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  Walter Roberson
      
      
 el 11 de En. de 2022
				Unfortunately that makes the code more difficult. You should consider upgrading.
if isunix()
    %for demonstration purposes only, position us to some images
    projectdir = fullfile(matlabroot, 'toolbox', 'images');
    cd(projectdir);
end
dinfo = dir('*');
dinfo(ismember({dinfo.name}, {'.', '..'})) = [];  %remove . and ..
folder_name = {dinfo.name}.';
num_folder = length(folder_name);
image_count = cell(num_folder, 1);
for K = 1 : num_folder
   finfo = dir( fullfile(folder_name{K}, '*.jpg') );
   image_count{K} = length(finfo);
end
results = [folder_name, image_count];
results
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  Image Analyst
      
      
 el 11 de En. de 2022
        
      Editada: Image Analyst
      
      
 el 11 de En. de 2022
  
      Do you want the count broken down by how many are in each folder?  Or do you just want to count the numbre in each folder and give a grand total, like this:
topLevelFolder = pwd; % or 'C:\my folder' or whatever you want.
filePattern = fullfile(topLevelFolder, '**\*.jpg');
% Get list of all JPG files in the top level folder and all subfolders below that.
fileList = dir(filePattern)
% Count them and put the count into the numFiles variable.
numFiles = length(fileList)
** may not work in your antique version though.  Not sure when the ** was introduced.
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