How to tabulate?
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prem kumar
el 29 de En. de 2022
Respondida: Voss
el 29 de En. de 2022
hello friends i want to ask a question regarding tabulation of number of days and sdelta without the statistic toolbox.
dn=1:1:365;
x=(360/365*(dn+284));
sdelta=23.45*(sind(x)*pi/180);
Tabulate sdelta for dn = 15, 45, 75, 105, 135, 165, 195, 225, 255, 285, 315, 345.
for normal tabulation for dn and sdelta is easy i believe but how about when the number of days is like this?i did thought about interpolation but i think it would not be that complicated and must have a simpler way to solve it ..can anyone give me a hint or guide me?.Thank you friends
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KSSV
el 29 de En. de 2022
You can use interp1.
dn=1:1:365;
x=(360/365*(dn+284));
sdelta=23.45*(sind(x)*pi/180);
dni = [15, 45, 75, 105, 135, 165, 195, 225, 255, 285, 315, 345] ;
sdeltai = interp1(dn,x,dni);
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Voss
el 29 de En. de 2022
You do not need to interpolate because the dn values you want the sdelta for are all already in the vector of all dn values (i.e., 1:1:365 contains 15, 45, 75, ...); you merely need to take those indices of sdelta:
dn=1:1:365;
x=(360/365*(dn+284));
sdelta=23.45*(sind(x)*pi/180);
dni = [15, 45, 75, 105, 135, 165, 195, 225, 255, 285, 315, 345];
sdeltai = sdelta(dni) % get elements of sdelta at indices dni
isequal(sdeltai,interp1(dn,sdelta,dni)) % same as "interpolating"
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