Suitable input for a function handle

Hellow friends,

I need to do something which I explain through a simple example. Consider the following

F=@(x,y,z)[x.*z.^2.*y;3.*x-y-2.*z;x.^2+y.^2+z.^2];

A1=[1 2 3];B1=num2cell(A1);

A2=[4 5 6];B2=num2cell(A2);

F(B1{:})

F(B2{:})

ans =

18

-5

14

ans =

720

-5

77

Now, I desire to do all the above calculations at once. I mean, I wish to do something as bellow (which throughs error)

>> A=[1 2 3;4 5 6];

B=num2cell(A);

F(B)

Not enough input arguments.

Error in @(x,y,z)[x.*z.^2.*y;3.*x-y-2.*z;x.^2+y.^2+z.^2]

I wish to get the following answer:

18 720

-5 -5

14 77

Any idea?

Thanks in advance,

Babak

Answer 1

[Walter Roberson]

F = @(x,y,z)[x.*z.^2.*y;3.*x-y-2.*z;x.^2+y.^2+z.^2];
A = [1 2 3;4 5 6];
B = cellfun(@transpose, num2cell(A, 1), 'uniform', 0)

B = 1×3 cell array
    {[1 4]}    {[2 5]}    {[3 6]}

F(B{:})

ans = 3×2

18 720 -5 -5 14 77

[Mohammad Shojaei Arani]

THanks a lot Walter for your VEEEEEEEEERY kind help!

[Steven Lord]

Another approach would involve breaking A up into appropriately sized pieces using mat2cell.

[Walter Roberson]

num2cell() is basically an easier interface around mat2cell.

output = num2cell(A, 1)

is

tsize = size(A);
nd = length(tsize);
temp = cell(1,nd);
temp{1} = ones(1,tsize(1));
for K = 2 : nd; temp{K} = tsize(K); end
output = mat2cell(A, temp{:})

(The code can be made shorter under the assumption that A has exactly 2 dimensions.)