ismember for string matrix

I have two string matrices;

A=['c1' 'c ' 'b '  'd9']'; %UNIQUELIST
B=['d9' 'c1']';            %ORIGINALLIST

I would like do find member of B in A, using:

[LIA,LOCB]=ismember(A,B);

and it returns

LOCB =
   3
   4
   3
   0
   0
   0
   1
   2

But I actually would like it to return matching row index like this:

LOCB =
   2
   0
   0
   1

Thanks for your help

Sam

Answer 1

[Sean de Wolski]

You need to make A and B cell arrays so that each string piece is a separate element (rather than a 1xn string. The fix is simple use {} instead of []

A={'c1' 'c ' 'b ' 'd9'}'; 
B={'d9' 'c1'}'

[LIA,LOCB]=ismember(A,B)

[Sam]

that hit the nail on the head, thanks!

Answer 2

[dpb]

You've got string arrays here; use the 'rows' optional argument to treat them as such instead of as individual characters...

>> [~,loc]=ismember(A,B,'rows')
loc =
   2
   0
   0
   1
>>

[Sam]

i guessed if i use

[~,loc]=ismember(cellstr(A),cellstr(B)) 
then it would safely do the same job?

[dpb]

Did you try it and see???

[Sean de Wolski]

Probably, but converting to cells is heavier weight if you don't need them for other things.