Suppression failure on evalin command

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Ian
Ian el 28 de Nov. de 2014
Editada: Jan el 12 de Ag. de 2017
I'm having a problem suppressing the evalin function when using it to change elements in a vector. The semi-colon isn't working. Is there a fix for this? Here's an example:
>> i=zeros(1,4);
>> evalin('base','i(1)=1');
i =
1 0 0 0
The semicolon doesn't suppress the output for some reason.

Respuesta aceptada

Mischa Kim
Mischa Kim el 28 de Nov. de 2014
Editada: Mischa Kim el 28 de Nov. de 2014
Ian, put the semi-colon right after the i(1)=1 statement
evalin('base','i(1)=1;')

Más respuestas (2)

Jan
Jan el 11 de Ag. de 2017
Editada: Jan el 12 de Ag. de 2017
It would be much more simple and efficient to omit the indirection over evalin:
i(1) = 1;
See the excellent explanations at tutorial:why-variables-should-not-be-named-dynamically-eval . You find a detailed analysis of the problems evalin causes here at: Answers: is-there-the-more-elegant-way-to-do-this#comment_476583

Ian
Ian el 28 de Nov. de 2014
So simple, yet so effective. Thanks!

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