Sum row 2 and stop when 1 is reached in row 1
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Iris Willaert
el 14 de Feb. de 2022
Comentada: Image Analyst
el 17 de Feb. de 2022
Hi,
I have a array of two rows with the following numbers:
Row1: [0,0,1,0,0,0,1,0,0,1,0]
Row2: [0.0220,0.3110,0.0230,1.0550,0.0230,0.0456,0.1120,0.0400,0.0660,0.3690]
I want to take the sum of row 2: until row 1 contains 1.
for example: 0.0220+0.3110, 0.0230 + 1.0550 + 0.0230 +0.0456
I tried to do this with a loop but it doesn't give me want I want.
for i = Row1
if(i == 0)
sum(Row2)
break;
end
if(i == 1)
break;
end
end
can anyone help me with this?
Thanks a lot!
0 comentarios
Respuesta aceptada
Image Analyst
el 14 de Feb. de 2022
Try using find():
Row1 =[0,0,1,0,0,0,1,0,0,1,0];
Row2 = [0.0220,0.3110,0.0230,1.0550,0.0230,0.0456,0.1120,0.0400,0.0660,0.3690];
oneIndexes = find(Row1 == 1)
% Find out where each stretch starts and stops.
startIndexes = [1, oneIndexes]
stopIndexes = [oneIndexes - 1, length(Row2)]
% Loop over each stretch, computing the sum in that stretch.
for k = 1 : length(startIndexes)
index1 = startIndexes(k);
index2 = stopIndexes(k);
theSums(k) = sum(Row2(index1 : index2));
end
theSums % Show in command window
2 comentarios
Image Analyst
el 17 de Feb. de 2022
You're welcome. Can you click the "Accept this answer" link for the best answer and click the Vote icon for both answers. 🙂
Más respuestas (1)
David Hill
el 14 de Feb. de 2022
Editada: David Hill
el 14 de Feb. de 2022
m= [0,0,1,0,0,0,1,0,0,1;0.0220,0.3110,0.0230,1.0550,0.0230,0.0456,0.1120,0.0400,0.0660,0.3690];
%rows of the same matrix must be the same size
f=[1,find(m(1,:))];
for k=2:length(f)
s(k-1)=sum(m(2,f(k-1):f(k)-1));
end
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