About "ismember" function

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Seongyun Kim
Seongyun Kim el 1 de Mzo. de 2022
Editada: Bruno Luong el 1 de Mzo. de 2022
How can I compute the answer for this example?
For example, I have two Excel files:
First Exel File -> PD
Var1 Var2
AAA 1
AA 2
A 3
BBB 5
BB 7
B 13
Second Excel File -> Ui
Var1 Var2 Var3 Var4
B 2 3 5
A 4 6 8
BB 6 7 1
B 2 1 6
A 2 8 1
AA 10 8 1
B 9 2 10
What I need to do is compare the values of Ui to the same rating value of PD. If the Value of Ui is greater than PD's value, it will be 1. Then, apply this method for each Var (Var2, Var3, and Var4).
For example, the first value of Ui, which is 2, must be compared with 13 which is a B rating in PD. And the output has to be 0 because Ui is smaller than PD's value.
Therefore, the output should be:
0 0 0
1 1 1
0 1 0
0 0 0
0 1 0
1 1 0
0 0 0
How can I do this with MatLab?
I asked similar thing before, but having error "Error using categorical/ismember (line 69)."
Thank you for your attention :)

Respuesta aceptada

Bruno Luong
Bruno Luong el 1 de Mzo. de 2022
Editada: Bruno Luong el 1 de Mzo. de 2022
No loop or arrayfun is needed
Var1=["AAA" "AA" "A" "BBB" "BB" "B"]';
Var2=[1 2 3 5 7 13]';
PD=table(Var1,Var2)
PD = 6×2 table
Var1 Var2 _____ ____ "AAA" 1 "AA" 2 "A" 3 "BBB" 5 "BB" 7 "B" 13
Var1=["B" "A" "BB" "B" "A" "AA" "B"]';
Var2=[2 4 6 2 2 10 9]';
Var3=[3 6 7 1 8 8 2]';
Var4=[5 8 1 6 1 1 10]';
UI=table(Var1,Var2,Var3,Var4)
UI = 7×4 table
Var1 Var2 Var3 Var4 ____ ____ ____ ____ "B" 2 3 5 "A" 4 6 8 "BB" 6 7 1 "B" 2 1 6 "A" 2 8 1 "AA" 10 8 1 "B" 9 2 10
[tf,loc]=ismember(UI(:,1),PD(:,1));
table2array(UI(tf,2:end))>=table2array(PD(loc(tf),2))
ans = 7×3 logical array
0 0 0 1 1 1 0 1 0 0 0 0 0 1 0 1 1 0 0 0 0

Más respuestas (2)

Simon Chan
Simon Chan el 1 de Mzo. de 2022
If you would like to use function ismember, then you may try the following:
value = arrayfun(@(x) PD.Var2(ismember(PD.Var1,x)),Ui.Var1); % Value to be compared
index = table2array(Ui(:,2:4))>=value; % Your output index

Arif Hoq
Arif Hoq el 1 de Mzo. de 2022
try this:
var1={'AAA' 1;'AA' 2;'A' 3;'BBB' 5;'BB' 7;'B' 13};
var2={'B' 2 3 5;'A' 4 6 8;'BB' 6 7 1;'B' 2 1 6;'A' 2 8 1;'AA' 10 8 1;'B' 9 2 10};
C=cell(1,7);
str={'B','A','BB','B','A','AA','B'}
str = 1×7 cell array
{'B'} {'A'} {'BB'} {'B'} {'A'} {'AA'} {'B'}
for n=1:7
idx(n)=find(ismember(var1(:,1),str(n)));
C{1,n}=cell2mat(var2(n,2:end))>=cell2mat(var1(idx(n),2));
end
matrix=[C{:}];
output=reshape(matrix,3,7)'
output = 7×3 logical array
0 0 0 1 1 1 0 1 0 0 0 0 0 1 0 1 1 0 0 0 0

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