Simulating dependent normally distributed variables using copulas

2 visualizaciones (últimos 30 días)
Alexandra
Alexandra el 10 de Dic. de 2014
Respondida: Tom Lane el 17 de Dic. de 2014
I created a model that simulates variables with kernel distributions connected by copula functions. (X and Y are series of ln returns)
It looks like this: kX = ksdensity(X,X,'function','cdf'); kY = ksdensity(Y,Y,'function','cdf'); [Rho,nu] = copulafit('t',[kX kY],'Method','ApproximateML'); r = copularnd('t',Rho,nu,100000); XX = r(:,1); YY = r(:,1); SX = ksdensity(X,XX,'function','icdf'); SY = ksdensity(Y,YY,'function','icdf'); SimX = a*exp(SX); SimY = b*exp(SY);
Now I wish to evaluate the results when modeling the variables as normally distributed. I can’t see what function can directly substitute ksdensity in the model. I was trying to do this with:
kX = normcdf(X); kY = normcdf(Y); [Rho,nu] = copulafit('t',[kX kY],'Method','ApproximateML'); r = copularnd('t',Rho,nu,100000); XX = r(:,1); YY = r(:,1); SX = norminv(X,XX); SY = norminv(Y,YY); SimX = a*exp(SX); SimY = b*exp(SY);
But is not working because norminv does not support the second argument with the copula function. I am seeing this right? What can I do?
Thank you very much,

Respuestas (1)

Tom Lane
Tom Lane el 17 de Dic. de 2014
Consider formatting your question so the code is not wrapped into the text.
The syntax ksdensity(x,xx) computes a kernel density based on x, evaluated at xx. If you intend to use the standard normal distribution, I believe you want just norminv(xx) .

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by