Bringing arrays to the same length
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There are three arrays (two vectors and a matrix), I need to bring them to the same length
a=[ 1.2,1.3,1.4]; % by array "a" i need to sort the values in array "b" and "m"
b=[ 1.2,0.9,1.3,2.6,1.4];
m=[1,2;26,90;1,2;120,0;1,0];
% what do i need to get
ba=[ 1.2,1.3,1.4];
ma=[1,2;1,2;1,0];
I will be glad to any advice
2 comentarios
DGM
el 2 de Mzo. de 2022
Editada: DGM
el 2 de Mzo. de 2022
At first glance, I thought you're looking for the intersections:
a=[1.2,1.3,1.4]; % by array "a" i need to sort the values in array "b" and "m"
b=[1.2,0.9,1.3,2.6,1.4];
m=[1,2;26,90;1,2;120,0;1,0];
ba = intersect(b,a)
ma = intersect(m,a)
... but there's no intersection between m and a. I don't know what rules you use to get the results you describe. Is ma a function of the indices of the intersection of b and a?
[ba idx] = intersect(b,a);
ma = m(idx,:)
Benjamin Kraus
el 2 de Mzo. de 2022
I'm having some trouble understanding your question.
If I understand correctly, you are trying to calculate the values in ba and ma based somehow on the values of a, b, and m, but I don't see how you calculate the values in ma from any of the vectors, and ba appears to be equal to a. Can you give more description (in words) of the algorithm you are hoping to use to derive ba and ma based on a, b, and m?
Respuestas (2)
Rik
el 2 de Mzo. de 2022
Editada: Rik
el 2 de Mzo. de 2022
There are two issues with the solution by Arif:
- It uses find on a logical array, but that is only used to index an array
- It assume the the first column in m will be 1 for all the rows we're looking for
The edits below solve both.
a=[ 1.2,1.3,1.4];
b=[ 1.2,0.9,1.3,2.6,1.4];
m=[1,2;26,90;1,2;120,0;1,0];
[L,idx]=ismember(a,b); % find the element of a in b
ba=a(L)
ma=m(idx(L),:)
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Arif Hoq
el 2 de Mzo. de 2022
Editada: Arif Hoq
el 2 de Mzo. de 2022
try this:
a=[ 1.2,1.3,1.4]; % by array "a" i need to sort the values in array "b" and "m"
b=[ 1.2,0.9,1.3,2.6,1.4];
m=[1,2;26,90;1,2;120,0;1,0];
[idx]=find(ismember(b,a)); % find the element of a in b
ba=b(idx)
ma=m((m==1),:) % find the first element=1
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