How can I manipulate with fields in structure.

I have struct s with 96 fields that have different names, each field is 44x1 column of numbers.

is it possible to divide all numbers in each field by some number, or use reshape to make from 44*1 to 11*4 matrix, or for example find max from each field and make a new array from those maximum values.

Answer 1

[Voss]

You can use structfun() for that:

% creating a struct like yours but with only 3 fields:
s = struct('field1',zeros(44,1),'field2',ones(44,1),'field3',randn(44,1))

s = struct with fields:
    field1: [44×1 double]
    field2: [44×1 double]
    field3: [44×1 double]

% divide by 7:
s_new = structfun(@(x)x/7,s,'UniformOutput',false)

s_new = struct with fields:
    field1: [44×1 double]
    field2: [44×1 double]
    field3: [44×1 double]

s_new.field2

ans = 44×1

0.1429 0.1429 0.1429 0.1429 0.1429 0.1429 0.1429 0.1429 0.1429 0.1429

% reshape:
s_new = structfun(@(x)reshape(x,11,4),s,'UniformOutput',false)

s_new = struct with fields:
    field1: [11×4 double]
    field2: [11×4 double]
    field3: [11×4 double]

% get the max:
s_max = structfun(@max,s)

s_max = 3×1

0 1.0000 2.6450

[Kiryl Zhaliazka]

Thank you so much!

[Voss]

You're welcome!

If that answers your question, please consider marking the answer as 'Accepted'. Thanks!

Answer 2

[Jan]

A loop over the field names can achieve this:

s = struct('field1',zeros(44,1),'field2',ones(44,1),'field3',randn(44,1));  % Thanks _
Field = fieldnames(s);
for k = 1:numel(Field)
   s.(Field{k}) = s.(Field{k}) / 17;
   % Or: s.(Field{k}) = reshape(s.(Field{k}), 4, 11);
end

This is done in structfun also, but the loop runs faster and is easier to read, in my opinion.