How to solve an implicit handle function with two variables?

Hi,

I have the following handle function:

Vd = @(V,I) V-I*R;
I = @(V,I) I0*(exp(Vd(V,I))-1);

How can I find I(V)=?

I0,R are constants.

Thanks

Answer 1

[Torsten]

I = @(V) -I0 + lambertw(I0*R*exp(I0*R+V))/R;

[Dor Gotleyb]

Thanks,

But is there a more general solution? In reality my functin (I) is more complex then the the Lambert W function, its a sum of various functions, among them is the exprasion I gave above.

[Torsten]

I don't know what you mean by "In reality my functin (I) is more complex then the the Lambert W function".

I = -I0 + lambertw(I0*R*exp(I0*R+V))/R 

solves the equation

I = I0*(exp(V-I*R)-1)

for I.

If your equation is more complex, use "fzero" or "fsolve".

[Dor Gotleyb]

I meant that my function is more complax then just I0*(exp(V-I*R)-1).

its a sum of several functions, but I didn't wont the quastion to be very long, just to understand the consept.

I = @(V,I) I0*(exp(Vd(V,I))-1) + a2*(exp(a3 * Vd(V,I))-1) + a1*sqrt(Vd(V,I)) + ...;

Ok, So I used 'fzero' as you suggested to solve for V=0:

F = @(0,I) -I + I0*(exp(Vd(0,I))-1);

Sol = fzero(F, 0);

And for other voltages I used the previous solution as a guess.

Thank you very mach