how to find the correct value of the matrix

anyone help me , when I excute this example , I didn't found in the matrix ''into'' the correct value.

x=[1 1 1 2 2 2 2 3 3 3];

d=0.1:0.1:1;

for ii=1:10

if ii==1:3

into(1:3)=x(1:3)*(d(1));

elseif ii==4:7

into(4:7)=x(4:7)*(d(1));

else

into(8:10)=x(8:10)*(d(1));

end

end

Answer 1

[Chunru]

x=[1 1 1 2 2 2 2 3 3 3];
d=0.1:0.1:1;

into = zeros(size(x));
for ii=1:10   
    if ii<=3
        into(ii)=x(ii)*(d(1));
    elseif ii<=7
        into(ii)=x(ii)*(d(1));
    else
        into(ii)=x(ii)*(d(1));
    end
end
into

into = 1×10

0.1000 0.1000 0.1000 0.2000 0.2000 0.2000 0.2000 0.3000 0.3000 0.3000

Answer 2

[Torsten]

into = zeros(10,1);
into(1:3)=x(1:3)*d(1);
into(4:7)=x(4:7)*d(1);
into(8:10)=x(8:10)*d(1);

or simply

into = x*d(1);

You can also use your loop, but as

into = zeros(10,1);
for i = 1:10
    if i <= 3
        into(i) = x(i)*d(1);
    elseif i >= 4 & i <= 7
        into(i) = x(i)*d(1);
    else
        into(i) = x(i)*d(1);
    end
end

But as said, it's not necessary to make it so difficult.

into = x*d(1)

is the best solution.