How to speed up for loop with if condition

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Nicolò Monaco
Nicolò Monaco el 17 de Mzo. de 2022
Respondida: M.B el 18 de Mzo. de 2022
Hello. I have the following code:
tilt = zeros(length(delta_tilt),width(delta_tilt));
for k= 1:(length(delta_tilt)-1)
tilt(k+1,:)= tilt(k,:)+delta_tilt(k+1,:);
for i= 1:365
if tilt(k+1,i)>constraint_up;
tilt(k+1,i)= constraint_up;
elseif tilt(k+1,i)<constraint_down;
tilt(k+1,i)= constraint_down;
end
end
end
Considering delta_tilt an array 86400*365, computational time for this operation results very heavy. There's any way to speed up this operation?
I want to build "tilt" as the cumsum of delta_tilt, but if the value k of tilt is out of boundaries, I want that the value k+1 takes in consideration this limitation.
Thanks in advance.

Respuesta aceptada

M.B
M.B el 18 de Mzo. de 2022
Not sure if it speeds up the code, but you can try the following:
tilt = 0*delta_tilt;
for k = 1:(size(delta_tilt, 1)-1)
tilt(k+1,:)= tilt(k,:)+delta_tilt(k+1,:);
tilt(k+1,:)= min(tilt(k+1,:),constraint_up);
tilt(k+1,:)= max(tilt(k+1,:),constraint_down);
end

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