What should I do to solve the problem that the content of the text added in the matlab drawing window is outside of the figure?

2 visualizaciones (últimos 30 días)
My code is as follows:
bp = boxplot(data_all);
set(bp,'LineWidth',1);
ax = gca;
ax.TickLength = [0.01 0.01];
ax.LineWidth =1;
ax.XTickLabel = {"A" 1:18};
ax.XColor ='K';
ax.FontName = 'Arial';
ax.FontSize = 10;
ax.XLabel.String = 'model';
ax.XLabel.FontName = '宋体';
ax.XLabel.FontSize = 14;
ax.XLabel.FontWeight = 'bold';
ax.YLabel.String = 'p/mm';
ax.YLabel.FontName = '宋体';
ax.YLabel.FontSize = 14;
ax.YLabel.FontWeight = 'bold';
xname = cmip.Model;
xname = string(xname);
xname = ["观测值";xname];
xname = ["A" ; string(1:N)'] + '-'+ xname;
h = text(20,mean(ax.YLim),xname,'HorizontalAlignment','left');
h.FontSize = 10;
Thanks you!
Best wishes!

Respuesta aceptada

Voss
Voss el 28 de Mzo. de 2022
Editada: Voss el 28 de Mzo. de 2022
You can adjust the axes and text Positions after everything else. See the bottom of the code below.
% made up data:
data_all = randn(100,19);
bp = boxplot(data_all);
set(bp,'LineWidth',1);
ax = gca;
ax.TickLength = [0.01 0.01];
ax.LineWidth =1;
ax.XTickLabel = {"A" 1:18};
ax.XColor ='K';
ax.FontName = 'Arial';
ax.FontSize = 10;
ax.XLabel.String = 'model';
ax.XLabel.FontName = '宋体';
ax.XLabel.FontSize = 14;
ax.XLabel.FontWeight = 'bold';
ax.YLabel.String = 'p/mm';
ax.YLabel.FontName = '宋体';
ax.YLabel.FontSize = 14;
ax.YLabel.FontWeight = 'bold';
% made up names:
xname = {'CESIII'; 'CMCCCC'; 'CMCBBB'; 'MPIII'; 'MRIIJKLMN'};
N = numel(xname);
xname = string(xname);
xname = ["观测值";xname];
xname = ["A" ; string(1:N)'] + '-'+ xname;
h = text(20,mean(ax.YLim),xname,'HorizontalAlignment','left');
h.FontSize = 10;
% adjust the axes width (ax.Position(3)) and text x (h.Position(1))
% by the width of the text (h.Extent(3)):
% need ax and h to be in the same Units:
h.Units = 'pixels';
ax.Units = 'pixels';
% perform the adjustment:
ax.Position(3) = ax.Position(3)-h.Extent(3);
h.Position(1) = h.Position(1)-h.Extent(3);
% restore the old Units:
ax.Units = 'normalized';
h.Units = 'data';
  2 comentarios
RYXChen
RYXChen el 29 de Mzo. de 2022
This method is very perfect!It solves this problem by setting the width of coordinate area. Thank you very much for your help! I learned a lot.
Best withes!

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