a run function gives an error due to size

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Berfin Çetinkaya
Berfin Çetinkaya on 2 Apr 2022
Commented: Jan on 3 Apr 2022
Hi
for bi= 1: 10;
bj= 1 : 10;
resultt(bi,bj) = birfazson(1,birfazson(2,:) == 1).'
end
I have such code in my file. When I run this it gives an error like this:
Unable to perform assignment because the size of the left side is 1-by-10 and the size of the right side is 5-by-1.
Error in pirellinew_02042022 (line 101)
resultt(bi,bj) = birfazson(1,birfazson(2,:) == 1).'
My right side values may change every time I run it. So what can I do in this situation?
  1 Comment
Jan
Jan on 2 Apr 2022
It depends on what you want to achieve. You didn't mention this yet.

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Answers (2)

Jan
Jan on 2 Apr 2022
Maybe:
resultt = nan(10, 10);
for bi = 1:10
r = birfazson(1, birfazson(2,:) == 1);
if ~isempty(r)
resultt(bi, 1:numel(r)) = r;
end
end
The body of the loop doe not depend on the loop counter bi. I assume, this is a simplification for the question in the forum.
  2 Comments
Jan
Jan on 3 Apr 2022
What does this mean: "wanted to find the sequences with 1 in the matrix"?
Please give us some example data for the input and the wanted output.

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VBBV
VBBV on 2 Apr 2022
Edited: VBBV on 2 Apr 2022
resultt(bi,bj) = birfazson(1,birfazson(2,:) == 1);
Ok. Check by removing transpose at the end
  1 Comment
VBBV
VBBV on 2 Apr 2022
By transposing the birfazson the arrays become incompatible.

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