Histogram plot by equal time intervals

Dear all,

I have with my the attached dataset that I will like to plot in an equal interval time histogram.

Below here is my code:

clc
A = load ('TutorialSampleT.txt');
Time = A (:,1) ;
x = A (:,2 ) ;
y = A (:,3 ) ;
z = A (:,4 ) ;
Amplitude = A (:,5) ; 
%define no of bins
noOfBins=min(Time):0.90:max(Time);
%plot histogram
histogram(Time,numel(noOfBins));
timeFormat=noOfBins;
timeFormat=timeFormat/24;
la=datestr(timeFormat,'HH:MM')
xticks(noOfBins);
xticklabels({la});

And the results:

I will be very happy if I can get some assistance with changing the time intervals to something more unifrom (an hour or 2 interval time will be perfect).

Thank you.

Answer 1

[Voss]

clc
A = load ('TutorialSampleT.txt');
Time = A (:,1) ;
x = A (:,2 ) ;
y = A (:,3 ) ;
z = A (:,4 ) ;
Amplitude = A (:,5) ; 

% interval in hours:
% interval = 0.9; 
% interval = 1;
interval = 2;

%define no of bins
noOfBins=min(Time):interval:max(Time);

%plot histogram
% histogram(Time,numel(noOfBins));
histogram(Time,numel(noOfBins)-1); % number of bins in the histogram is one less than numel(noOfBins), i.e., noOfBins defines the bin edges
timeFormat=noOfBins;
timeFormat=timeFormat/24;
la=datestr(timeFormat,'HH:MM');
xticks(noOfBins);
xticklabels({la});

[Greek McCoy]

Hello,

Thank you very much for your answer.

It works perfectly well for me.

--

Sincerely,

Greek

[Voss]

You're welcome!

Answer 2

[Steven Lord]

Rather than specifying the number of bins you could specify the bin edges explicitly.

minutesPerDay = minutes(days(1));
T = datetime('today');
dt = T + minutes(randi(minutesPerDay, 1, 1000));
edges = T + hours(0:2:24);
histogram(dt, edges)
xticks(edges)

[Greek McCoy]

Hello,

Thank you very much for your response.

Your answer is very valuable to me and works well with my code.

I am definitely going to incorporate it in my code.

--

Sincerely,

Greek