How to create readable decision trees

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Awais Saeed
Awais Saeed el 10 de Abr. de 2022
Comentada: Christopher McCausland el 12 de Abr. de 2022
I am trying to produce a binary decision tree as following:
% Dataset
r2 = [0;0;1;0;1;0;0;1];
r3 = [0;0;0;0;0;1;1;0];
r4 = [0;1;1;1;1;1;1;0];
Group = [1;1;1;1;1;2;2;3];
T = table(r2,r3,r4,Group)
T = 8×4 table
r2 r3 r4 Group __ __ __ _____ 0 0 0 1 0 0 1 1 1 0 1 1 0 0 1 1 1 0 1 1 0 1 1 2 0 1 1 2 1 0 0 3
% 'Group' is the target in dataset T
model = fitrtree(T, 'Group', 'MinParentSize', 1);
% View the model as a graph
view(model,'Mode','graph');
The decision tree that MATLAB gave me is shown in MatlabTree.png. I also produced a tree for the same dataset using Latex and that is shown in LatexTree.png.
I want MATLAB to display parent nodes same as Latex tree's parent node. For example, Matlab's tree says "r3>0.5 r3>=0.5", which is not as good to read as Latex generated tree. Can this Matlab tree be made more readable like the Latex one?

Respuestas (1)

Christopher McCausland
Christopher McCausland el 11 de Abr. de 2022
Hi Awais,
I had a similar problem with Markov chains recently. I ended up using digrapgh() to solve the problem, that being said its still a lot of work.
Kind regards,
Christopher
  2 comentarios
Awais Saeed
Awais Saeed el 12 de Abr. de 2022
Thanks for the suggestion @Christopher McCausland. digrapgh() is not as easy, efficient and exact as fitrtree(). I searched on the internet and it seems that the appearance cannot be changed. Let's hope that MATLAB will offer this ability in future releases.
Christopher McCausland
Christopher McCausland el 12 de Abr. de 2022
Hi Awis,
Digraph isn't as easy you are correct, it does look good when its finsihed though. To make it quicker you can call parameters already created in 'model' Esentially you create model, use graphplot() to generate your nodes and lines and then use digraph() and plot() to generate the new plot based on the inputs from 'model'.
I hope you can get something sorted, I will have a go myself later and see if I can get anything!
Christopher

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