Sorting the vector y wrt the vector x?

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MEET SHAH
MEET SHAH el 16 de Abr. de 2022
Respondida: Image Analyst el 17 de Abr. de 2022
I have two vectors x and y
x = 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 0.66
y = 0.051998 0.084698 0.117398 0.150098 0.182798 0.215498 0.248198 0.19 0.09 0.235118
I want to make the matrix [x,y] in such a way that x is in ascending, i.e., results should be
x = 0.1 0.2 0.3 0.4 0.5 0.6 0.66 0.7 0.8 0.9
y = 0.051998 0.084698 0.117398 0.150098 0.182798 0.215498 0.235118 0.248198 0.19 0.09
Any suggestions are apreciated and thankyou in advance for your help !!

Respuesta aceptada

Voss
Voss el 16 de Abr. de 2022
x = [ 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 0.66 ];
y = [ 0.051998 0.084698 0.117398 0.150098 0.182798 0.215498 0.248198 0.19 0.09 0.235118 ];
[~,idx] = sort(x);
M = [x(idx); y(idx)]
M = 2×10
0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.6600 0.7000 0.8000 0.9000 0.0520 0.0847 0.1174 0.1501 0.1828 0.2155 0.2351 0.2482 0.1900 0.0900

Más respuestas (1)

Image Analyst
Image Analyst el 17 de Abr. de 2022
Slightly different but essentially the same
x = [0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 0.66];
y = [0.051998, 0.084698, 0.117398, 0.150098, 0.182798, 0.2154908, 0.248198, 0.19, 0.09, 0.235118];
% Sort (and replace) x and get the order in which it was sorted.
[x, sortOrder] = sort(x, 'ascend')
x = 1×10
0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.6600 0.7000 0.8000 0.9000
sortOrder = 1×10
1 2 3 4 5 6 10 7 8 9
% Sort y using the same order as x used, replacing original y with new, sorted y.
y = y(sortOrder)
y = 1×10
0.0520 0.0847 0.1174 0.1501 0.1828 0.2155 0.2351 0.2482 0.1900 0.0900

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