Best fitting curve for variable data
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    Somnath Kale
 el 23 de Abr. de 2022
  
Hello
I was trying fitting to fit the following data
x = 1.0779    1.2727    1.4700  1.5766    1.6471    1.7396   1.7828    1.8208    1.8370
y = 7.9511    9.8400   12.8838   15.1925   31.0055   36.0292   62.5528   87.9648  176.4142
for the equation:
y = a exp(b*(1/x)^c)
where a ba nd c are fitting paramters.
I triesd the fiting but unfortinately i was not able to magae it. It will be really helpful experties can guide me in this context.
Thanks in advance!
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Respuesta aceptada
  Matt J
      
      
 el 23 de Abr. de 2022
        
      Editada: Matt J
      
      
 el 23 de Abr. de 2022
  
      Using fminspleas from the File Exchange
% data 
x = [1.0779    1.2727    1.4700  1.5766    1.6471    1.7396   1.7828    1.8208    1.8370]' ; 
y = [7.9511    9.8400   12.8838   15.1925   31.0055   36.0292   62.5528   87.9648  176.4142]' ; ;
funlist={1,@(c,xx) (1./xx).^c};
[c,ab]= fminspleas(funlist,-3,x,log(y),-inf,0);
a=exp(ab(1));
b=ab(2);
a,b,c
xx=linspace(min(x),max(x),100);
fun=@(x)a*exp(b*(1./x).^c);
plot(x,y,'o',xx,fun(xx))
ylim([0,max(y)])
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Más respuestas (1)
  KSSV
      
      
 el 23 de Abr. de 2022
        
      Editada: KSSV
      
      
 el 23 de Abr. de 2022
  
      % data 
x = [1.0779    1.2727    1.4700  1.5766    1.6471    1.7396   1.7828    1.8208    1.8370]' ; 
y = [7.9511    9.8400   12.8838   15.1925   31.0055   36.0292   62.5528   87.9648  176.4142]' ; ;
eqn = @(a,b,c,x) a*exp(b*(1./x).^c) ; % equation to fit  
% Define Start points
x0 = [1 1 1]; 
% fit-function 
fitfun = fittype(eqn);
% fit curve
[fitted_curve,gof] = fit(x,y,fitfun,'StartPoint',x0)
% Save the coeffiecient values for a,b,c 
coeffvals = coeffvalues(fitted_curve);
% Plot results
scatter(x, y, 'bs')
hold on
plot(x,fitted_curve(x),'r')
legend('data','fitted curve')
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