There is a problem with the find function

Why is the y (row) of points C and D wrong? Is there something wrong with me calling the function? Isn't the output of find() an array?

1 comentario

Jonas
Jonas el 28 de Abr. de 2022
we can not check your results because your screenshot shows only the columns 133 to 144
may your view be the problem, scroll to the left and look at the first column of the last row

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Riccardo Scorretti
Riccardo Scorretti el 28 de Abr. de 2022
Editada: Riccardo Scorretti el 28 de Abr. de 2022
Dear 文辉 沈 ,
the result you obtain is quite logical. Consider the following example:
bw = zeros(4, 5) ; bw(end,2:4) = 1
bw = 4×5
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 0
You are working on the last row only:
bw(end,:)
ans = 1×5
0 1 1 1 0
The command find(bw(end,:)) will return all the values for which the condition bw(end,:) is verified, that is bw(end,:)~=0. These values are of course all equal to 1. In this case, find will return an array of values (yc) and an array of index (xc):
[yc, xc] = find(bw(end,:))
yc = 1×3
1 1 1
xc = 1×3
2 3 4
The command find(bw(end,:), 1, 'first') will return only one couple [value, index] (because of the argument 1) for which the condition is satisfied, starting from the beginning (because of 'first'):
[yc, xc] = find(bw(end,:), 1, 'first')
yc = 1
xc = 2
Similarly for the following case, but starting from the end:
[yd, xd] = find(bw(end,:), 1, 'last')
yd = 1
xd = 4

5 comentarios

文辉 沈
文辉 沈 el 28 de Abr. de 2022
I know what you mean,how can i make it to put 227 as it's row ?
Riccardo Scorretti
Riccardo Scorretti el 28 de Abr. de 2022
I don't understand the question. Could you provide the full matrix bw and the expected result?
clc;
close all;
clear;
workspace;
format long g;
format compact;
%选择待图像输入文件夹
selpath = uigetdir(path);
if ~isequal(selpath,0)
pathname_old = selpath;
else
warndlg('selpath fail','warning');
return
end
%选择处理完成的图像输出文件夹
selpath = uigetdir(path);
if ~isequal(selpath,0)
pathname_new = selpath;
else
warndlg('selpath fail','warning');
return
end
%dir()获得指定文件夹下的所有子文件夹和文件,并存放在一种文件结构体数组
filelList = dir(fullfile(pathname_old,'*.jpg'));
n = length(filelList);
for i = 1:n
filename_old = filelList(i).name;
filename_new=strcat(filename_old(1:end-4),"_processed",".jpg");
rgbImage=imread(fullfile(pathname_old,filename_old));
%图像增强
adimage = imadjust(rgbImage,stretchlim(rgbImage));
%灰度图
I = im2gray(adimage);
%高斯低通滤波,9*9
G = fspecial('gaussian',[9,9],1);
GS = imfilter(I,G);
%阈值分割
sh = graythresh(GS);
bw = im2bw(GS,sh);
bw = ~bw;
bw = imfill(bw, 'holes');
bw = bwareafilt(bw, 1);
%第一行 起始点A 、 结束点B
[ya, xa] = find(bw(1,:), 1, 'first');
[yb, xb] = find(bw(1,:), 1, 'last');
%最后一行 起始点C 、 结束点D
[yc, xc] = find(bw(end,:), 1, 'first');
[yd, xd] = find(bw(end,:), 1, 'last');
dab = pdist2([xa, ya],[xb, yb]);
dac = pdist2([xa, ya],[xc, yc]);
dad = pdist2([xa, ya],[xd, yd]);
dbc = pdist2([xb, yb],[xc, yc]);
dbd = pdist2([xb, yb],[xd, yd]);
dcd = pdist2([xc, yc],[xd, yd]);
[mi] = [dab,dac,dad,dbc,dbd,dcd];
length = max(mi);
boundaries = bwboundaries(bw);
numberOfBoundaries = size(boundaries, 1);
imshow(rgbImage);
hold on;
for k=1:numberOfBoundaries
thisBoundary = boundaries{k};
x = thisBoundary(:,2);
y = thisBoundary(:,1);
plot(x,y,'g-','LineWidth',2);
end
plot([xa, xd],[1, 227],'b','LineWidth',2);
text((xa+xd)/2,(1+227)/2,[' ','Length = ',num2str(length)],'Color','b');
hold off;
frame = getframe;
im = frame.cdata;
pathfilename_new=fullfile(pathname_new,filename_new);
imwrite(im,pathfilename_new);
end
disp("ok~");
This is a process of my image processing, bw data can be viewed after running.
My expectation is to calculate the length of the crack, first to get the coordinates of the boundary point, the problem is here.
%%%%%%Off topic:Of course I have other pictures (with different directions of the cracks), but before solving those pictures I want to finish the calculations for this picture
The 1 and 227 in the script are just for this picture, so my idea is whether I can output 1 and 227 automatically instead of manually entering it
plot([xa, xd],[1, 227],'b','LineWidth',2);
text((xa+xd)/2,(1+227)/2,[' ','Length = ',num2str(length)],'Color','b');
Sorry for the delay. I'm still not sure to have understood: in your code 227 is just the size of the image (= all the cracks are more or less vertical and take the whole image)?
clc;
close all;
clear;
workspace;
format long g;
format compact;
%选择待图像输入文件夹
selpath = uigetdir(path);
if ~isequal(selpath,0)
pathname_old = selpath;
else
warndlg('selpath fail','warning');
return
end
%选择处理完成的图像输出文件夹
selpath = uigetdir(path);
if ~isequal(selpath,0)
pathname_new = selpath;
else
warndlg('selpath fail','warning');
return
end
%dir()获得指定文件夹下的所有子文件夹和文件,并存放在一种文件结构体数组
filelList = dir(fullfile(pathname_old,'*.jpg'));
n = length(filelList);
for i = 1:n
filename_old = filelList(i).name;
filename_new=strcat(filename_old(1:end-4),"_processed",".jpg");
rgbImage=imread(fullfile(pathname_old,filename_old));
%图像增强
adimage = imadjust(rgbImage,stretchlim(rgbImage));
%灰度图
I = im2gray(adimage);
%高斯低通滤波,9*9
G = fspecial('gaussian',[9,9],1);
GS = imfilter(I,G);
%阈值分割
sh = graythresh(GS);
bw = im2bw(GS,sh);
bw = ~bw;
bw = imfill(bw, 'holes');
bw = bwareafilt(bw, 1);
%第一行 起始点A 、 结束点B
[ya, xa] = find(bw(1,:), 1, 'first');
[yb, xb] = find(bw(1,:), 1, 'last');
%最后一行 起始点C 、 结束点D
[yc, xc] = find(bw(end,:), 1, 'first');
[yd, xd] = find(bw(end,:), 1, 'last');
dab = pdist2([xa, ya],[xb, yb]);
dac = pdist2([xa, ya],[xc, yc]);
dad = pdist2([xa, ya],[xd, yd]);
dbc = pdist2([xb, yb],[xc, yc]);
dbd = pdist2([xb, yb],[xd, yd]);
dcd = pdist2([xc, yc],[xd, yd]);
[mi] = [dab,dac,dad,dbc,dbd,dcd];
length = max(mi);
boundaries = bwboundaries(bw);
numberOfBoundaries = size(boundaries, 1);
imshow(rgbImage);
hold on;
for k=1:numberOfBoundaries
thisBoundary = boundaries{k};
x = thisBoundary(:,2);
y = thisBoundary(:,1);
plot(x,y,'g-','LineWidth',2);
end
val = size(bw,1); % ***
plot([xa, xd],[1, val],'b','LineWidth',2); % ***
text((xa+xd)/2,(1+val)/2,[' ','Length = ',num2str(length)],'Color','b'); % ***
hold off;
frame = getframe;
im = frame.cdata;
pathfilename_new=fullfile(pathname_new,filename_new);
imwrite(im,pathfilename_new);
end
disp("ok~");
If this is not what you need, plese clarify and send more images.

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el 28 de Abr. de 2022

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el 29 de Abr. de 2022

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