getting an error in this code
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clc
clear
%shipcostpmf.m
sx = (1:8);
px = [0.15*ones(4,1), 0.1*ones(4,1)];
gx = (sx<=5).*(105*sx-5*(sx.^2)) + ((sx>5).*500);
sy = unique(gx);
fprintf('sy =\n');
disp(sy);
py = finitepmf(gx,px,sy);
not sure why my py is getting an error because it says Unrecognized function or variable 'finitepmf'. but finitepmf should be a command?
Respuesta aceptada
Más respuestas (2)
Voss
el 29 de Abr. de 2022
Maybe finitepmf should be defined as follows:
function pmf=finitepmf(sx,px,x)
% finite random variable X:
% vector sx of sample space
% elements {sx(1),sx(2), ...}
% vector px of probabilities
% px(i)=P[X=sx(i)]
% Output is the vector
% pmf: pmf(i)=P[X=x(i)]
pmf=zeros(size(x(:)));
for i=1:length(x)
pmf(i)= sum(px(find(sx==x(i))));
end
end
which was found here:
If that seems right and you haven't done so already, put that code into an m-file called finitepmf.m. If you have done that already, then make sure that finitepmf.m is on your MATLAB search path.
Mathieu NOE
el 29 de Abr. de 2022
hi
here you are
sx = (1:8);
px = [0.15*ones(4,1), 0.1*ones(4,1)];
gx = (sx<=5).*(105*sx-5*(sx.^2)) + ((sx>5).*500);
sy = unique(gx);
fprintf('sy =\n');
disp(sy);
py = finitepmf(gx,px,sy)
function pmf=finitepmf(sx,px,x)
% finite random variable X:
% vector sx of sample space
% elements {sx(1),sx(2), ...}
% vector px of probabilities
% px(i)=P[X=sx(i)]
% Output is the vector
% pmf: pmf(i)=P[X=x(i)]
pmf=zeros(size(x(:)));
for i=1:length(x)
pmf(i)= sum(px(sx==x(i)));
end
end
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