assigning argument of function within function

% complete function
function f = fix(x) 
% x is an array of 10 arguments
% these functions
% function1
% function2
% function3 
% function4 
% function5
% are already there.
% 
% I have assigned an array 'x'; now i want to assign the following functions these arguments but ....
% i am getting an error the way i do is as below.
a=function1(x(1),x(2),x(4))
b =function2(x(2),x(5),x(10))
c = function3 (x(3))
d =function4 (x(10),x(9))
e=function5(x(6),x(7),x(8))
fix=a+b+c+d+e;

end

how can i do it.

[Jan]

Which error message do you get? This information is important, so it is a good idea to share it with the readers.

What is "function1" etc.? I cannot guess this detail.

One typo:

  fix=a+b+c+d+e;
% ^^^ No, not the name of the function, but "f", the output variable

By the way, "fix" is a built-in function. Shadowing it by a user-defined function can cause severe side-effects.

Answer 1

[Davide Masiello]

The error is in the last line of the function fix.

Change that and the code works.

fix(rand(1,10))

ans = 6.0073

% complete function
function f = fix(x) 
% x is an array of 10 arguments
% these functions
% function1
% function2
% function3 
% function4 
% function5
% are already there.
% 
% I have assigned an array 'x'; now i want to assign the following functions these arguments but ....
% i am getting an error the way i do is as below.
a=function1(x(1),x(2),x(4));
b =function2(x(2),x(5),x(10));
c = function3 (x(3));
d =function4 (x(10),x(9));
e=function5(x(6),x(7),x(8));
f=a+b+c+d+e;
end

function out = function1(a,b,c)
out = a+b+c;
end
function out = function2(a,b,c)
out = a+b+c;
end
function out = function3(a)
out = a;
end
function out = function4(a,b)
out = a+b;
end
function out = function5(a,b,c)
out = a+b+c;
end