Does somebody know how to plot this function?

I have the exercise to plot this function:

I have to use an anonymous function

That's my code until now:

figure; hold on;

y = @(x) tan(3*x) + 5*x-4;

x = linspace(0,180);

plot(x, y(x) ,'c');

axis([0 180 -100 1000]);

title('Funktion y = tan(3x)+5x-4');

xlabel('x-Werte[°]');

ylabel('Funktionswerte');

But I don't know how to get the parts between the tangent 
or if my solution is even the right beginning, can somebody help?

Answer 1

[Voss]

Use tand rather than tan, because the argument 3*x is in degrees rather than radians.

Increase the number of points to see the asymptotes better. Here I've used 1000 points total.

figure; hold on;
y = @(x) tand(3*x) + 5*x-4;
x = linspace(0,180,1000);
plot(x, y(x) ,'c');
axis([0 180 -100 1000]);

[Sabrina Bitz]

Thanks a lot!!

[Sabrina Bitz]

There's something missing I realize now: There needs to be space between the tands, what can be seen in the original, how do I get them?

[Voss]

Probably the easiest way to do that is to use fplot instead of plot:

figure; hold on;
y = @(x) tand(3*x) + 5*x-4;
fplot(y,[0 180],'c');
axis([0 180 -100 1000]);

[Sabrina Bitz]

How is it possible with plot? It says specificially plot in the exercise

[Voss]

Including the exact values of x where tan(3x) goes to infinity seems to work ok.

figure; hold on;
y = @(x) tand(3*x) + 5*x-4;
x = sort([linspace(0,180,1000) 30:60:180]);
plot(x, y(x) ,'c');
axis([0 180 -100 1000]);

[Sabrina Bitz]

Thank you!!

[Voss]

You're welcome!