Extend a cell array of dates (from days only, to hours and days) in a compact way
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Sim
el 17 de Mayo de 2022
Comentada: Sim
el 18 de Mayo de 2022
I have a cell vector containing 44 dates, i.e. days:
>> C
ans =
44×1 cell array
{'17-Jun-2017'}
{'18-Jun-2017'}
{'19-Jun-2017'}
...
{'28-Jul-2017'}
{'29-Jul-2017'}
{'30-Jul-2017'}
I would like to "extend" that cell vector to include the 24 hours as well, in each day.
This means that my cell vector will pass from 44 elements (i.e. the 44 days) to 24 * 44 = 1056 elements (i.e. 24 hours in each day). Something like this:
% Desired Output (something like this)
>> D
ans =
1056×1 cell array
{'17-Jun-2017 00:00:00'}
{'17-Jun-2017 01:00:00'}
{'17-Jun-2017 02:00:00'}
...
{'17-Jun-2017 23:00:00'}
{'18-Jun-2017 00:00:00'}
{'18-Jun-2017 01:00:00'}
{'18-Jun-2017 02:00:00'}
...
{'29-Jul-2017 23:00:00'}
{'30-Jul-2017 00:00:00'}
Any idea on how to do it in a compact way ?
Maybe there is a simple in-built function in Matlab to do that, and that I am probably missing right now..
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Star Strider
el 17 de Mayo de 2022
Editada: Star Strider
el 17 de Mayo de 2022
Try this —
C1 = {'17-Jun-2017'; '30-Jul-2017'}
DT1 = [datetime(C1{1}) : days(1) : datetime(C1{end})]'
DT2 = [min(DT1): hours(1) : max(DT1)]'
C2 = compose('%s',string(DT2))
It simply creates a new datetime vector with a different increment from the original cell array, and then uses the compose function to create a new cell array from that. (I would keep it as a datetime array rather than converting it back to a cell array.)
.
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Más respuestas (3)
Mitch Lautigar
el 17 de Mayo de 2022
Use for loops. Here's an untested example of what I mean.
stack_array = [];
for i = 1:length(C)
curr_date = C(i);
for j = 1:24
stack_array = [stack_array;cell(strjoin(cellstr(curr_date),'-',num2str(j)) )];
end
end
In theory, this code would loop through and for every date in your C loop, add in the hours with a dash in the middle to keep the formatting you have above. Hope it helps!
2 comentarios
Mitch Lautigar
el 17 de Mayo de 2022
stack_array = [stack_array;cell(strjoin(cellstr(curr_date),'-',num2str(j)) )]; should be:
stack_array = [stack_array; cell(strjoin(cellstr(curr_date),'-',num2str(j),'') )]; forgot to tell strjoin how to join the command.
Steven Lord
el 17 de Mayo de 2022
I'd probably take advantage of implicit expansion for datetime and duration arrays, introduced for those types in release R2020b.
C = {'17-Jun-2017'; '18-Jun-2017'; '19-Jun-2017'}
theDays = datetime(C).'
theHours = hours(0:23).'
D = theDays + theHours; % Adding a row vector and a column vector gives a matrix
D = reshape(D, [], 1)
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