How i implement Adams Predictor-Corrector Method from general code ?

Below is the Adams predictor-corrector formula and general code. How can I adapt this code to the above question? Can you please help?
%------------------------------------------------------
% 2-step Predictor-Corrector
% [T,Y]=dd2(f,definition,y,h); definition=[t1,tfinal]
%------------------------------------------------------
function [T,Y]=dd2(f,definition,Y1,h)
t1=definition(1);tfinal=definition(2);T=t1;Y=Y1;
t2=t1+h;
definition=[t1,t2];
[T,Y]=rk2(f,definition,Y1,h) ;
Y2=Y(2);
while t2 <tfinal
t3=t2+h;
P=Y2+h*(3/2*f(t2,Y2)-1/2*f(t1,Y1));
Y3=Y2+h/12*(5* f(t3,P)+8*f(t2,Y2)-f(t1,Y1));
Y1=Y2; Y2=Y3;t1=t2;t2=t3;
T=[T;t3];Y=[Y;Y3];
end
%
%----------------------------------------------

2 comentarios

Would this kind of code be correct for the BDF method? @Lateef Adewale Kareem
You know the correct result of your differential equation.
If you plot Y against T in the calling program and compare the plot with the analytical solution, both should be approximately the same.
If yes, your code is (most probably) correct, if not, it's not.

Iniciar sesión para comentar.

 Respuesta aceptada

clc; clear all;
h = 0.01;
mu = 20;
f_m = @(t,y) mu*(y-cos(t))-sin(t);
exact = @(t) exp(mu*t)+cos(t);
[t,y_m] = dd2(f_m,[0, 1],exact(0), exact(h), h);
plot(t, exact(t)); hold
Current plot held
plot(t,y_m);
%plot(t,y,'-o');
legend('Exact Solution','Adams predictor-corrector formula')
xlabel('t')
ylabel('y')
title('When h = 0.01 and µ=20')
%------------------------------------------------------
% 2-step Predictor-Corrector
% [T,Y]=dd2(f,definition,y,h); definition=[t1,tfinal]
%------------------------------------------------------
function [T,Y] = dd2(f, definition, Y1, Y2, h)
t1 = definition(1); tfinal = definition(2); t = t1:h:tfinal;
T = t(1:2)'; Y = [Y1;Y2];
for i = 2:numel(t)-1
P = Y(i) + h/2*(3*f(t(i),Y(i))-f(t(i-1),Y(i-1)));
Y(i+1) = Y(i) + h/12*(5*f(t(i+1), P) + 8*f(t(i),Y(i)) - f(t(i-1),Y(i-1)));
T=[T;t(i+1)];
end
end
%

4 comentarios

You implemented rk4, not rk2.
Hazel Can
Hazel Can el 30 de Mayo de 2022
Editada: Hazel Can el 30 de Mayo de 2022
I replaced RK4 with RK2. The solution has moved a little away from the exact solution. Was there any particular reason to use RK4 or would RK2 be correct as well?
As far as I read in your assignment, you should use the exact solution for y1. So neither rk2 nor rk4 is needed.
yeah. he should have sent it in. I have modified the solution to use the exact solution at h

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Function Creation en Centro de ayuda y File Exchange.

Productos

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by