Not having Integration result

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Mohammad Humaun Kabir
Mohammad Humaun Kabir el 27 de Mayo de 2022
Comentada: Torsten el 27 de Mayo de 2022
I am trying to integrate this function using the code -
----------------
syms x
xd = 700/319
fun = ((x^4)* exp(x))/((exp(x) -1)^2);
cv = int(fun,0,xd)
--------------
But, I am getting same form of the function like that -
>> Cv_calculatior
cv =
int((x^4*exp(x))/(exp(x) - 1)^2, x, 0, 700/319)
What's wrong here??

Respuesta aceptada

Torsten
Torsten el 27 de Mayo de 2022
Editada: Torsten el 27 de Mayo de 2022
Using "int", MATLAB tries to find an analytical antiderivative for your function, but cannot find one.
Use numerical integraion using "integral" instead. Don't start at 0 since your function has a division by zero at this location.
fun = @(x) x.^4.*exp(x)./(exp(x) -1).^2;
xd = 700/319;
result = integral(fun,1e-16,xd)
  2 comentarios
Mohammad Humaun Kabir
Mohammad Humaun Kabir el 27 de Mayo de 2022
Editada: Mohammad Humaun Kabir el 27 de Mayo de 2022
Thanks. Would you like to help me to write the whole code. Here is my problem -
Varying temparature from 0 degree to 800 degree with 2 degree interval ( T = 0:2:800)
integrating this function, y = ((x.^4).* exp(x))./((exp(x) -1).^2) for 0 to T, where T has a range of data
Expecting result: a list of data, T vs y
Torsten
Torsten el 27 de Mayo de 2022
fun = @(x) x.^4.*exp(x)./(exp(x) -1).^2;
T = [1e-16,2:2:800];
y(1) = 0;
for i = 2:numel(T)
y(i) = y(i-1) + integral(fun,T(i-1),T(i));
end
plot(T,y)

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