how to know 'y' values perpendicular to a line?
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I have longitude, latitude, altitude data of aircraft. and I plotted trajectoris of aircrafts(I only drawed mean trajecorty here. and drawed 2D)
a left image is what I plotted with patch(using percentile). but it's something wrong.
percentile ex) If percentile is 100, the patch contain every trajectory. In my case, I use 97.5 percentile.
I need to plot like a right image. the line between two y values should be perpendicular to a mean trajectory(black line).
I know it's because I assgin two y values(not to mean trajetroy's y value) to same value as mean trajectory's y value.
but I don't know how to get a two y values which is perpendicular to each mean trajectory point.
I will attach my code for your understanding.
Thanks.
for i = 1:length(33R)
plot3(33R(i).Longitude, 33R(i).Latitude,33R(i).BAlt)
hold on
end
hold on
xlabel('X')
ylabel('Y')
zlabel('Z')
yv = [];
yv = [yv;mean_trajectory.Latitude]; % I fixed 'y' values I think it's a problem.
for i = 1:length(trajectory) % trajectory is every trajectory of aicraft incluing mean trajectory.
xptcl = prctile(trajectory(i).Longitude,[2.5 97.5]); % I used percentile when making a patch
zptcl = prctile(trajectory(i).Altitude,[2.5 97.5]); % same
xl(i,:) = xptcl;
zl(i,:) = zptcl;
patch([xptcl flip(xptcl)], [0 0 0 0]+yv(i), [[1 1]*zptcl(1) [1 1]*zptcl(2)],'r', 'FaceAlpha',0.5)
end
plot3(xl(:,1), yv(:), zl(:,1), '-k', 'LineWidth',2)
plot3(xl(:,1), yv(:), zl(:,2), '-k', 'LineWidth',2)
plot3(xl(:,2), yv(:), zl(:,1), '-k', 'LineWidth',2)
plot3(xl(:,2), yv(:), zl(:,2), '-k', 'LineWidth',2)
grid on
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