If statement dictating acceptable range is not functioning properly, why?
6 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Aly Osman
el 10 de Jun. de 2022
Comentada: Aly Osman
el 10 de Jun. de 2022
I'm working on a project to where I have to find pairs of values that provide the same output when inputted into an equation. I want only combinations that provide an output within a defined range, so for example, say I want all the possible combinations of values that sum to 6 +/- 0.5 so combinations that would sum to 5.5, 6 or 6.5 are all acceptable, however if there's a combination that sums to 7, I want that to be excluded. Getting a code working that at least satisfies the process of finding combinations is something I already have, thanks to the gracious people on here in this thread , so my issue is setting the condtions that I just spoke of to exclude certain combinations.
In my test code however, it doesn't seem like this is being done for some reason. I want all combinations that give me a value that is between lim1 and lim2, however when plugging the combinations that are output back into the original equation to find davg, I find that it has cominations that output values way beyond the conditions that I set (for example davg(1)= 89.3, when I set a condition for no combinations that would result in davg being greater than 59.663). So is something off with my if statement, or am I off base here completely? I would appreciate some insight regarding this.
value1= deg2rad(35);
value2=deg2rad(27);
davg_initial= rad2deg(atan((cot(value2)+cot(value1))*0.5));
lim1=(davg_initial-0.5);
lim2= (davg_initial+0.5);
a = [0:0.5:35];
n = length(a);
b = [];
for i = 1:n
value1 = a(i);
for j = 1:n
value2 = a(j);
davg= rad2deg(atan((cot(value2)+cot(value1))*0.5));
if davg<=lim2 && davg>=lim1...
&& value2<value1
b = [b,[value1;value2]];
end
end
end
b'
x=deg2rad(b(1,:));
y=deg2rad(b(2,:));
davg= rad2deg(atan((cot(y)+cot(x))*0.5));
2 comentarios
Steven Lord
el 10 de Jun. de 2022
Just a suggestion: rather than repeatedly converting back and forth between degrees and radians I recommend using the degree-based trig functions. Here's a simple example:
format longg
s = sind(35);
s2 = sin(deg2rad(35));
[s; s2] % Compare answers using radians and degrees
c = cosd(35);
c2 = cos(deg2rad(35));
[c; c2]
ct = cotd(35);
ct2 = cot(deg2rad(35));
[ct; ct2]
% Check: cot(x) = cos(x)/sin(x)
check = [ct; c./s]
Respuesta aceptada
Geoff Hayes
el 10 de Jun. de 2022
@Aly Osman - what are the units for a and so the units for b? In your looping code, that includes the if statement, you do
for i = 1:n
value1 = a(i);
for j = 1:n
value2 = a(j);
davg= rad2deg(atan((cot(value2)+cot(value1))*0.5));
if davg<=lim2 && davg>=lim1...
&& value2<value1
b = [b,[value1;value2]];
end
end
end
where you take pairs of values from a and pass them into the equation
davg= rad2deg(atan((cot(value2)+cot(value1))*0.5));
If the criteria is met, then you save value1 and value2 to the b array. Once the outer loop completes, then you seem to do a check or validation of the data
x=deg2rad(b(1,:));
y=deg2rad(b(2,:));
davg= rad2deg(atan((cot(y)+cot(x))*0.5));
where you convert each value in b from degrees to radians, and then you pass them into the (almost identical) equation
davg= rad2deg(atan((cot(y)+cot(x))*0.5));
So why is there a conversion from degress to radians of the data in b? Shouldn't you have done that also when extracting value1 and value2 from a?
Más respuestas (0)
Ver también
Categorías
Más información sobre Logical en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!