replace dlmread file name with a variable in a loop

I have around 20 files needed to be read and plotted. So the file names are such as file.288.10 , file.288.100 etc. I have 20 files. I am tryng in the following code, but its not reading T and P.
for T = [288 299 308 323 337]
for P = [10 100 340 544]
M = dlmread('file.T.P', ' ', 1, 0);
figure
plot (M(:,1), M(:,2))
hold on
plot (M(:,1), M(:,3))
hold on
end
end

 Respuesta aceptada

Maybe this:
folder = pwd; % Or wherever you want
for T = [288 299 308 323 337]
for P = [10 100 340 544]
baseFileName = sprintf('file.%d.%d.csv', T, P); % Change extension if it's not csv.
fullFileName = fullfile(folder, baseFileName);
if isfile(fullFileName)
M = readmatrix(fullFileName);
figure
plot (M(:,1), M(:,2), 'b-', 'LineWidth', 2)
grid on;
hold on
plot (M(:,1), M(:,3), 'r-', 'LineWidth', 2)
legend('Column 2', 'Column 3');
title(baseFileName, 'FontSize', 18)
else
fprintf('Warning: file not found : "%s".\n', fullFileName)
end
end
end
If that doesn't work, attach two of your files in a zip file after reading this:

Más respuestas (2)

dpb
dpb el 12 de Jun. de 2022
You've got to turn the numerics into string filename to build dynamically --
for T = [288 299 308 323 337]
for P = [10 100 340 544]
fname=sprintf('file%d.%d',T,P);
M = dlmread(fname,' ', 1, 0);
figure
plot (M(:,1), M(:,2:3))
end
end
Unless you've an older release of MATLAB, I'd suggest using readmatrix instead of dlmread

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Preguntada:

el 12 de Jun. de 2022

Respondida:

el 12 de Jun. de 2022

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