How would I take the mean of each row from column_13 of 79 csv files?
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muhammad choudhry
el 17 de Jun. de 2022
Comentada: Karim
el 17 de Jun. de 2022
Hi,
I am completely stuck here. I am trying to take the mean of each row of column 13 in the 79 csv files and there are 48 rows in total in each file but I am struggling to make a code here. I anyone can help.
Code tried so far:
close all; clear all; clc;
P = 'F:\3-PIV_Experimental_Data\Calculations_TurbulentIntensity\line_Data\Elliptical_Side_LSB\Length\DesignPoint\110_outlet';
S = dir(fullfile(P,'*.csv'));
N = natsortfiles({S.name});
TurbulentFluctuationArray_Mean=zeros(numel(N), 1);
for i = 1:numel(N);
data = readtable( fullfile(P, N{i}) ); % read the csv files
col_13(i) = mean([data(:,13)])
end
Error:
Error using sum
Invalid data type. First argument must be numeric or logical.
Error in mean (line 127)
y = sum(x, dim, flag) ./ mysize(x,dim);
Error in rowMean_practise (line 10)
col_13(i) = mean([data(:,13)],79)
2 comentarios
Respuesta aceptada
Karim
el 17 de Jun. de 2022
Editada: Karim
el 17 de Jun. de 2022
You were almost there, you just need to convert the table to an array to take the mean of the values, see below for a quick fix:
P = 'F:\3-PIV_Experimental_Data\Calculations_TurbulentIntensity\line_Data\Elliptical_Side_LSB\Length\DesignPoint\110_outlet';
S = dir(fullfile(P,'*.csv'));
N = natsortfiles({S.name});
TurbulentFluctuationArray_Mean=zeros(numel(N), 1);
col_13_data = zeros(48,numel(N))
for i = 1:numel(N);
data = readtable( fullfile(P, N{i}) ); % read the csv files
col_13_data(:,i) = table2array( data(:,13) ); % get the 13th column of each file
end
col_13_mean = mean(col_13_data ,2 ); % get the mean value for each row, over the files
2 comentarios
Karim
el 17 de Jun. de 2022
ok i think i understand what you mean, i update the example code accordingly
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