How to obtain a matrix from the iterations of a for loop?
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Pietro Fiondella
el 21 de Jun. de 2022
Comentada: Voss
el 21 de Jun. de 2022
I woud like to obtain a matrix C[84x24] with every row filled, by the moltiplication between each row af a Matrix A[7x24] by each element of vector B[1x12].
I am able to do it only by this loop with "cell command at the end but i'm looking for an easyer way .
A=[ 0.2167 0.2467 0.2520 0.2652 0.2661 0.2907 0.3498 0.4211 0.5348 0.5735 0.5242 0.4361 0.4810 0.5233 0.5365 0.5356 0.5533 0.7629 0.8317 0.8704 0.7770 0.7321 0.6563 0.5427
0.2406 0.2738 0.2797 0.2944 0.2954 0.3227 0.3883 0.4675 0.5936 0.6367 0.5819 0.4841 0.5340 0.5809 0.5956 0.5946 0.6142 0.8469 0.9232 0.9663 0.8626 0.8127 0.7286 0.6024
0.2440 0.2778 0.2837 0.2986 0.2996 0.3274 0.3938 0.4742 0.6021 0.6458 0.5902 0.4910 0.5416 0.5892 0.6041 0.6031 0.6230 0.8591 0.9364 0.9801 0.8749 0.8244 0.7390 0.6111
0.2453 0.2792 0.2851 0.3001 0.3011 0.3290 0.3958 0.4766 0.6052 0.6490 0.5932 0.4935 0.5444 0.5922 0.6072 0.6062 0.6261 0.8634 0.9412 0.9850 0.8794 0.8285 0.7428 0.6142
0.2453 0.2792 0.2851 0.3001 0.3011 0.3290 0.3958 0.4766 0.6052 0.6490 0.5932 0.4935 0.5444 0.5922 0.6072 0.6062 0.6261 0.8634 0.9412 0.9850 0.8794 0.8285 0.7428 0.6142
0.2448 0.2786 0.2846 0.2995 0.3005 0.3284 0.3950 0.4756 0.6040 0.6477 0.5920 0.4925 0.5433 0.5910 0.6060 0.6050 0.6249 0.8617 0.9393 0.9831 0.8776 0.8268 0.7413 0.6129
0.2369 0.2696 0.2754 0.2899 0.2908 0.3178 0.3823 0.4603 0.5845 0.6269 0.5730 0.4767 0.5258 0.5720 0.5865 0.5855 0.6048 0.8340 0.9091 0.9514 0.8494 0.8003 0.7174 0.5932];
B=[0.999; 0.992; 0.939; 0.850; 0.810; 0.803; 0.796; 0.792; 0.821; 0.929; 0.990; 1.000];
for j=1:12;
C=A*B(j);
cell_C{j}=C;
end
D=[cell_C{1,1};cell_C{1,2};cell_C{1,3};cell_C{1,4};cell_C{1,5};cell_C{1,6};cell_C{1,7};cell_C{1,8};cell_C{1,9};cell_C{1,10};cell_C{1,11};cell_C{1,12}];
D
0 comentarios
Respuesta aceptada
Voss
el 21 de Jun. de 2022
Editada: Voss
el 21 de Jun. de 2022
A=[ 0.2167 0.2467 0.2520 0.2652 0.2661 0.2907 0.3498 0.4211 0.5348 0.5735 0.5242 0.4361 0.4810 0.5233 0.5365 0.5356 0.5533 0.7629 0.8317 0.8704 0.7770 0.7321 0.6563 0.5427
0.2406 0.2738 0.2797 0.2944 0.2954 0.3227 0.3883 0.4675 0.5936 0.6367 0.5819 0.4841 0.5340 0.5809 0.5956 0.5946 0.6142 0.8469 0.9232 0.9663 0.8626 0.8127 0.7286 0.6024
0.2440 0.2778 0.2837 0.2986 0.2996 0.3274 0.3938 0.4742 0.6021 0.6458 0.5902 0.4910 0.5416 0.5892 0.6041 0.6031 0.6230 0.8591 0.9364 0.9801 0.8749 0.8244 0.7390 0.6111
0.2453 0.2792 0.2851 0.3001 0.3011 0.3290 0.3958 0.4766 0.6052 0.6490 0.5932 0.4935 0.5444 0.5922 0.6072 0.6062 0.6261 0.8634 0.9412 0.9850 0.8794 0.8285 0.7428 0.6142
0.2453 0.2792 0.2851 0.3001 0.3011 0.3290 0.3958 0.4766 0.6052 0.6490 0.5932 0.4935 0.5444 0.5922 0.6072 0.6062 0.6261 0.8634 0.9412 0.9850 0.8794 0.8285 0.7428 0.6142
0.2448 0.2786 0.2846 0.2995 0.3005 0.3284 0.3950 0.4756 0.6040 0.6477 0.5920 0.4925 0.5433 0.5910 0.6060 0.6050 0.6249 0.8617 0.9393 0.9831 0.8776 0.8268 0.7413 0.6129
0.2369 0.2696 0.2754 0.2899 0.2908 0.3178 0.3823 0.4603 0.5845 0.6269 0.5730 0.4767 0.5258 0.5720 0.5865 0.5855 0.6048 0.8340 0.9091 0.9514 0.8494 0.8003 0.7174 0.5932];
B=[0.999; 0.992; 0.939; 0.850; 0.810; 0.803; 0.796; 0.792; 0.821; 0.929; 0.990; 1.000];
kron method:
D_test = kron(B,A)
Compare to the cell array method:
for j=1:12;
C=A*B(j);
cell_C{j}=C;
end
D=vertcat(cell_C{:});
The result is the same:
isequal(D_test,D)
2 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Matrices and Arrays en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!