I want to obtain value of "W" for different combination of values of (psi,r) example. "W" for (psi=0.0001,r = 2.1891) ; (psi=0.001,r = 2.1940); (psi=0.01,r = 2.2373) and so on

2 visualizaciones (últimos 30 días)
psi = 0.001;
alpha = (12*psi)^(1/3);
r = 2.1940;
l1 = (r + alpha)*(r + alpha);
l1a = r*r - r*alpha + alpha*alpha;
L1 = log(l1/l1a);
t1 = (2*r - alpha) / (alpha*sqrt(3));
T1 = atan(t1);
l2 = (1 + alpha)*(1 + alpha);
l2a = (1*1) - (1*alpha) + (alpha*alpha);
L2 = log(l2/l2a);
t2 = (2*1 - alpha) / (alpha*sqrt(3));
T2 = atan(t2);
W1 = 4 * sqrt(3) * (T1 - T2) * log((r+alpha)/(1+alpha));
W2 = (L1 - L2)*log((r*r - r*alpha + alpha*alpha)/(1 - alpha + alpha*alpha));
W3 = 4*(T1 -T2)*(T1 -T2);
W4 = (L1 - L2) + 2 * sqrt(3) * (T1 - T2);
W5 = 3 ./ ((r - 1) * (r - 1));
W = ((W1 + W2 -W3) * W5)/W4
  2 comentarios
Dyuman Joshi
Dyuman Joshi el 22 de Jun. de 2022
Editada: Dyuman Joshi el 22 de Jun. de 2022
Make it a function and call from workspace.
%calling individually
W1=calculateW(0.0001,2.1891)
W1 = 0.1602
W2=calculateW(0.001,2.194)
W2 = 0.1595
W3=calculateW(0.01,2.2373)
W3 = 0.1534
function W = calculateW(psi,r)
alpha = (12*psi)^(1/3);
l1 = (r + alpha)*(r + alpha);
l1a = r*r - r*alpha + alpha*alpha;
L1 = log(l1/l1a);
t1 = (2*r - alpha) / (alpha*sqrt(3));
T1 = atan(t1);
l2 = (1 + alpha)*(1 + alpha);
l2a = (1*1) - (1*alpha) + (alpha*alpha);
L2 = log(l2/l2a);
t2 = (2*1 - alpha) / (alpha*sqrt(3));
T2 = atan(t2);
W1 = 4 * sqrt(3) * (T1 - T2) * log((r+alpha)/(1+alpha));
W2 = (L1 - L2)*log((r*r - r*alpha + alpha*alpha)/(1 - alpha + alpha*alpha));
W3 = 4*(T1 -T2)*(T1 -T2);
W4 = (L1 - L2) + 2 * sqrt(3) * (T1 - T2);
W5 = 3 ./ ((r - 1) * (r - 1));
W = ((W1 + W2 -W3) * W5)/W4;
end
AVINASH SAHU
AVINASH SAHU el 22 de Jun. de 2022
thank you for clarification but how can we use loop so that we don't have to enter manually for large dataset?

Iniciar sesión para comentar.

Respuesta aceptada

Dyuman Joshi
Dyuman Joshi el 22 de Jun. de 2022
%loop
psi=[0.0001,0.001,0.01];
r=[2.1891,2.194,2.2373];
for i=1:numel(psi)
W(i)=calculateW(psi(i),r(i));
end
W
W = 1×3
0.1602 0.1595 0.1534
%arrayfun
W1=arrayfun(@calculateW, psi, r)
W1 = 1×3
0.1602 0.1595 0.1534
function W = calculateW(psi,r)
alpha = (12*psi)^(1/3);
l1 = (r + alpha)*(r + alpha);
l1a = r*r - r*alpha + alpha*alpha;
L1 = log(l1/l1a);
t1 = (2*r - alpha) / (alpha*sqrt(3));
T1 = atan(t1);
l2 = (1 + alpha)*(1 + alpha);
l2a = (1*1) - (1*alpha) + (alpha*alpha);
L2 = log(l2/l2a);
t2 = (2*1 - alpha) / (alpha*sqrt(3));
T2 = atan(t2);
W1 = 4 * sqrt(3) * (T1 - T2) * log((r+alpha)/(1+alpha));
W2 = (L1 - L2)*log((r*r - r*alpha + alpha*alpha)/(1 - alpha + alpha*alpha));
W3 = 4*(T1 -T2)*(T1 -T2);
W4 = (L1 - L2) + 2 * sqrt(3) * (T1 - T2);
W5 = 3 ./ ((r - 1) * (r - 1));
W = ((W1 + W2 -W3) * W5)/W4;
end

Más respuestas (0)

Categorías

Más información sobre Loops and Conditional Statements en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by