How can I display all elements of an array in a single row?
24 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
hi, if I have an array, how I can display all elements in single row if I did not know the length of that row(i did not know the no. of columns) . where the size of rows is not equal
for ex.
A=CGCKCCD?QDCQC??FE?N?NBCBNM?AEZE*GAAWE?E-GQE?R?N??Y
G?GRHTHYH?H*HMHDHPH?HLHWGMHH?Y?AHCGYGAHEGBG?E?HRG*
HKHFIMI*GKITHPI-LRH?GRH?IBGSL?I?IXIFLAIYIZISHLHQIK
GRH?HKIGGPHPIHIELELILHLRIDQWLDLCAWGGGDLQHQ?L
GLQ?FEN-LLKBGAE??-?BNDNMLTELK?KXK?NHEADX?ACBAWMGK?
G?EWGMHFHWGRIVHPHSIAHZGNGKHBS?GCCZE*K*GY?EHHGVN?ND
GRHQHMGNISBSEYLQFHBPIBIWBTCKN?VLC?AWKAR-?ZCZC?P?A*
IVEWSHF?P?KWSPYEBWGVHQHIBYG??QLYQHAWPEPN
GMHFG?HAH?IFEBIMSPVFMFR?A*VXSAQRPMN?CFA?YNB?C?TFYB
G?XFGKGRBWIKXMI?XPHKH*XSHMIDGNXKGDNDQ?XCN?N-HNXQZM
THANKS
4 comentarios
Walter Roberson
el 5 de Oct. de 2011
A(3,:)
However, it is not possible to have a numeric array that has rows of different lengths.
Depending on the data type and the needs of your program, you might be able to use some particular flag value to indicate the logical end of data in the row. For example if the flag value was 255, then you could use
t = A(3,:);
L = find(t == 255,1) - 1;
if isempty(L); L = length(t); end
t(1:L)
Respuestas (3)
Walter Roberson
el 5 de Oct. de 2011
I am not sure what you are asking, but the below seems like a plausible answer:
a1 = cellstr(A);
fprintf('%s ', a1{:}); fprintf('\n');
0 comentarios
Dr. Seis
el 5 de Oct. de 2011
If the string "A" also has end of line characters, then:
strf = strfind(A,sprintf('\n'));
B = {''};
if ~isempty(strf)
B = cellstr(A(1:strf(1)-1));
if numel(strf) > 1
for ii = 2 : numel(strf)
B(ii) = cellstr(A(strf(ii-1)+1:strf(ii)-1));
end
B(ii+1) = cellstr(A(strf(ii)+1:end));
else
B(2) = cellstr(A(strf(1)+1:end));
end
else
B = cellstr(A);
end
Where "B" is now a cell array. You can access/convert any row back to a string by, for example:
row_string = char(B(some_row));
3 comentarios
Dr. Seis
el 5 de Oct. de 2011
Ah, cool. I don't have to do this anymore:
fprintf('%s',char(t(some_row)));
Robert
el 5 de Oct. de 2011
Arrays cannot have different numbers of columns in each row. Maybe you're dealing with a cell array, in which case you'd just type: A{3} For an array you'd type A(3,:).
3 comentarios
Ver también
Categorías
Más información sobre Matrix Indexing en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!