square wave not "limited"
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Federico Paolucci
el 30 de Jun. de 2022
Respondida: Jon
el 30 de Jun. de 2022
hi, I produced this square wave signal, but as you can see the square peaks have no upper limit. how can i solve?
x=0.03*square(f*t,duty)
in reality I seem to see that the graph is the other way around
0 comentarios
Respuesta aceptada
Jon
el 30 de Jun. de 2022
You probably are not correctly specifiying the duty cycle. If you want the square wave to be "on" half the time you should set duty = 50, also note that the first argument to square is in radians, so each cycle is 2*pi radians. You have to scale your input accordingly.
0 comentarios
Más respuestas (1)
Sam Chak
el 30 de Jun. de 2022
Doesn't seem to have any issue.
t = linspace(0, 3*pi, 3001)';
f = 2;
duty = 50;
x = 0.03*square(f*t, duty);
plot(t/pi, x, t/pi, 0.03*sin(2*t))
grid on
ylim([-0.05 0.05])
0 comentarios
Ver también
Categorías
Más información sobre Multirate Signal Processing en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!