Unrecognized function or variable 'e1'.
s1=x3.^2+x1*x3+x1.^2;
s2=x1.^4+x1.^3*x3+x1.^2*x3.^2 +x1.^2*x3.^2+x1*x3.^3 + x3.^4;
%s1=x2.^2+x1*x2+x1.^2;
%s2=x1.^4+x1.^3*x2+x1.^2*x2.^2 +x1.^2*x2.^3 + x2.^4;
%u1 = -e1-e2;
%u2 = beta*e1*k1 +gamma*e1*k2+omegaf*e1-ff2*cos(W2*t)+ff1*cos(W1*t);
u1 = -e2-e1;
u2 = beta*e1*s1 + gamma*e1*s2+omegaf*e1-ff2*cos(W2*t)+ff1*cos(W1*t);
%sys-I
dx1=x2;
dx2=-alpha*x2-omegaf*x1-beta*x1.^3- gamma*x1.^5+ff1*cos(W1*t);
%sys -II
dx3=x4+u1;
dx4=-alpha*x4-omegaf*x3-beta*x3.^3- gamma*x3.^5+ff2*cos(W2*t)+u2;
de1=dx3-dx1;
de2=dx4-dx2;
e1 = x3-x1;
e2= x4-x2;
de1=e2+u1;
de2=-alpha*e2-omegaf*e1-beta*e1*s1- gamma*e1*s2+ff2*cos(W2*t)-ff1*cos(W1*t)+u2;
dy = [dx1; dx2; dx3; dx4];
end

2 comentarios

prajith samraj
prajith samraj el 18 de Jul. de 2022
i need e1 and e2 graph. what can i do?
e1 = y(:,3)-y(:,1);
e2= y(:,4)-y(:,2);

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 Respuesta aceptada

Sam Chak
Sam Chak el 19 de Jul. de 2022
Try manipulating the parameters to get different results.
% Solver
tspan = [0 20];
x10 = 0.11;
x20 = 0.1;
x30 = 0.21;
x40 = 0.2;
y0 = [x10; x20; x30; x40];
[t, y] = ode45(@(t, y) f(t, y), tspan, y0);
% Plots
e1 = y(:, 3) - y(:, 1);
e2 = y(:, 4) - y(:, 2);
subplot(2,1,1)
plot(t, e1), grid on, xlabel('t'), ylabel('e_{1}')
subplot(2,1,2)
plot(t, e2), grid on, xlabel('t'), ylabel('e_{2}')
function dy = f(t, y)
% parameters
alpha = 0.5;
omegaf = -1;
beta = 0.8790;
gamma = 0.3000;
W1 = 1.4450;
ff1 = 0.5381;
W2 = 1.4450;
ff2 = 0.5381;
% assignment
x1 = y(1);
x2 = y(2);
x3 = y(3);
x4 = y(4);
e1 = x3 - x1;
e2 = x4 - x2;
s1 = x3^2 + x1*x3 + x1^2;
s2 = x1^4 + (x1^3)*x3 + (x1^2)*(x3^2) + (x1^2)*(x3^2) + x1*(x3^3) + x3^4;
u1 = - e2 - e1;
u2 = beta*e1*s1 + gamma*e1*s2 + omegaf*e1 - ff2*cos(W2*t) + ff1*cos(W1*t);
% sys I
dx1 = x2;
dx2 = - alpha*x2 - omegaf*x1 - beta*x1^3 - gamma*x1^5 + ff1*cos(W1*t);
% sys II
dx3 = x4 + u1;
dx4 = - alpha*x4 - omegaf*x3 - beta*x3^3 - gamma*x3^5 + ff2*cos(W2*t) + u2;
de1 = dx3 - dx1;
de2 = dx4 - dx2;
dy = [dx1; dx2; dx3; dx4];
end

2 comentarios

prajith samraj
prajith samraj el 19 de Jul. de 2022
i need the value of e1dot and e2 dot graph
Sam Chak
Sam Chak el 19 de Jul. de 2022
@prajith samraj, I'm a little confused now. In your comment, you clearly mentioned that you need e1 and e2 graph. Perhaps, you unintentionally confused yourself with e1dot and e2dot?
Please edit the title of your question for clarity...

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