the program is plotted once, then showing error, is something error in program
13 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
SAHIL SAHOO
el 21 de Jul. de 2022
Respondida: KSSV
el 21 de Jul. de 2022
format long
a = 0;
b = 4;
h = 0.1;
k = 0.033;
L = 0.5;
s = 0.1;
tc = 70E-9;
n = (b-a)/h ;
t = a + (0:n)*h;
y(1) = 0;
func1 = @(y) ((-(s^2)*k/tc)*sin(y - pi/2) + L*(s^2)/(2*tc)*sin(y + pi/2)/sqrt(1 + cos(y + pi/2)));
for i = 1:n
k1 = func1(y(i));
k2 = func1 (y(i)+(k1/2)*h);
k3 = func1 (y(i)+(k2/2)*h);
k4 = func1(y(i)+(k3*h));
y(i+1) = y(i) + (h/6)*(k1+(2*(k2+k3))+k4);
end
plot(t,y)
==================================
output:- Error using plot
Vectors must be the same length.
2 comentarios
KSSV
el 21 de Jul. de 2022
It is working fine...clear you variables once and run the code.
a = 0;
b = 4;
h = 0.1;
k = 0.033;
L = 0.5;
s = 0.1;
tc = 70E-9;
n = (b-a)/h ;
t = a + (0:n)*h;
y(1) = 0;
func1 = @(y) ((-(s^2)*k/tc)*sin(y - pi/2) + L*(s^2)/(2*tc)*sin(y + pi/2)/sqrt(1 + cos(y + pi/2)));
for i = 1:n
k1 = func1(y(i));
k2 = func1 (y(i)+(k1/2)*h);
k3 = func1 (y(i)+(k2/2)*h);
k4 = func1(y(i)+(k3*h));
y(i+1) = y(i) + (h/6)*(k1+(2*(k2+k3))+k4);
end
whos t y
plot(t,y)
Respuesta aceptada
KSSV
el 21 de Jul. de 2022
You initialize the value of y before for loop.
y = zeros(1,n) ;
y(1) = 0;
func1 = @(y) ((-(s^2)*k/tc)*sin(y - pi/2) + L*(s^2)/(2*tc)*sin(y + pi/2)/sqrt(1 + cos(y + pi/2)));
0 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Discrete Data Plots en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
