Comparing Rows of Char Array to String
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Hi everyone,
I have an 8x3 char array that looks like the following
Wed
Wed
Wed
Wed
Wed
Wed
Wed
Sat
I need to compare it to a string to perform one action when the day is Wednesday (or Wed) and a different action when the day is Saturday (or Sat). For i = 1:8, a loop runs to put the output of this if statement into a numeric vector.
How can I go about properly comparing each row of the char array to a string ('Wed' or 'Sat')?
Thanks in advance!
Respuestas (1)
Guillaume
el 11 de Feb. de 2015
c = ['Wed'; 'Wed'; 'Fri'; 'Wed'; 'Sat'];
[~, actionnumber] = ismember(c, ['Wed'; 'Sat'], 'rows')
4 comentarios
Justin Duval
el 11 de Feb. de 2015
Guillaume
el 11 de Feb. de 2015
There's nothing particularly wrong about your approach which uses a loop. Depending on how similar the actions are, I would probably personally use arrayfun and function handles to dispatch to each actions, but it's more a matter of style.
One nitpick is that you shouldn't be using == to compare string, strcmp is more robust:
if strcmp(dayname(i, :), 'Wed')
Additionally, knowing that programs can grow, rather than if ... else, I'd use switch ... case statements. It's much easier to add actions in the future. As an added bonus, switch use strcmp when given strings:
switch dayname(i, :)
case 'Wed'
%do someting
case 'Sat'
%do something
end
I don't really like the fact that your else does not explictly state it applies to 'Sat'. What if your string ends up being 'Thu'. Again the case is more explicit.
Image Analyst
el 11 de Feb. de 2015
Even more robustness can be gained by casting the day to lower case if you don't really care about the case of the letters. Or you could use strcmpi(). If you don't care about case then it's most robust if your code works regardless if they capitalized the day or not.
if strcmp(lower(dayname(i, :)), 'wed')
if strcmpi(dayname(i, :), 'Wed')
switch lower(dayname(i, :))
case 'wed'
Justin Duval
el 11 de Feb. de 2015
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