Comparing Rows of Char Array to String

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Justin Duval
Justin Duval el 11 de Feb. de 2015
Comentada: Justin Duval el 11 de Feb. de 2015
Hi everyone,
I have an 8x3 char array that looks like the following
Wed
Wed
Wed
Wed
Wed
Wed
Wed
Sat
I need to compare it to a string to perform one action when the day is Wednesday (or Wed) and a different action when the day is Saturday (or Sat). For i = 1:8, a loop runs to put the output of this if statement into a numeric vector.
How can I go about properly comparing each row of the char array to a string ('Wed' or 'Sat')?
Thanks in advance!

Respuestas (1)

Guillaume
Guillaume el 11 de Feb. de 2015
Use the second output of ismember with the 'rows' option:
c = ['Wed'; 'Wed'; 'Fri'; 'Wed'; 'Sat'];
[~, actionnumber] = ismember(c, ['Wed'; 'Sat'], 'rows')
  4 comentarios
Image Analyst
Image Analyst el 11 de Feb. de 2015
Even more robustness can be gained by casting the day to lower case if you don't really care about the case of the letters. Or you could use strcmpi(). If you don't care about case then it's most robust if your code works regardless if they capitalized the day or not.
if strcmp(lower(dayname(i, :)), 'wed')
if strcmpi(dayname(i, :), 'Wed')
switch lower(dayname(i, :))
case 'wed'
Justin Duval
Justin Duval el 11 de Feb. de 2015
Thanks for the extra input. My code does cover other days of the week as well, I was just including the simplest case based on the set of data in my original post as it was all I needed to convey my problem.
I will swap out the == operator for strcmp, and I will look into switch case statements as well, they look nice.
Thanks again!

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