plot based on if and else condition

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Malar Vizhi
Malar Vizhi el 14 de Ag. de 2022
Comentada: Malar Vizhi el 16 de Ag. de 2022
GoodEvening Sir/Mam,
I'm working in intesity of speech .I have classified it based om maximum to minimum energy but i dont know how to plot them.Please help me as possible
[x,fs] = audioread("sa.wav");
%end
si = 0.020;Fsi=si*fs;t=(0:1/Fsi);
frames=framing(x,fs,Fsi);
[r,c] = size(frames);
signal = zeros(size(0));
for i = 1:r
signal(i) = sum(frames(i,:).^2);
end
A=zeros(1,length(signal));
B=zeros(1,length(signal));
C=zeros(1,length(signal));
D=zeros(1,length(signal));
sig = max(signal);
for j=1:length(signal)
I(j)=(signal(j)/sig);
if(0.9<=I(j)<=1)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0.6<=I(j)<=0.8)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0.4<I(j)<=0.6)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0.2<=I(j)<=0.5)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0<=I(j)<=0.1)
A(j)=I(j);
plot(A,'b-');hold on
end
end

Respuestas (4)

Torsten
Torsten el 14 de Ag. de 2022
MATLAB does not accept "double inequalities".
Thus instead of
if a < b < c
you will have to use
if a < b && b < c
Further, you should plot A completely after the if-clause, not after every value of j.
Further, you missed to classify the cases 0.8 < l(j) < 0.9, 0.4 < l(j) < 0.5 and 0.1 < l(j) < 0.2. Or should A remain 0 in these cases ?
  3 comentarios
Malar Vizhi
Malar Vizhi el 14 de Ag. de 2022
Sir i have change my code but the plot is not changed
Torsten
Torsten el 14 de Ag. de 2022
I can't answer anything useful without the modified code ...

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Malar Vizhi
Malar Vizhi el 14 de Ag. de 2022
[x,fs] = audioread("sa.wav");
%end
si = 0.020;Fsi=si*fs;t=(0:1/Fsi);
frames=framing(x,fs,Fsi);
[r,c] = size(frames);
signal = zeros(size(0));
for i = 1:r
signal(i) = sum(frames(i,:).^2);
end
%
% plot(signal,'bo');
A=zeros(1,length(signal));
B=zeros(1,length(signal));
C=zeros(1,length(signal));
D=zeros(1,length(signal));
sig = max(signal);
for j=1:length(signal)
I(j)=(signal(j)/sig);
if(0.9<=I(j)) && (I(j)<=1)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0.6<=I(j)) && (I(j)<=0.9)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0.4<I(j)) && (I(j)<=0.6)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0.2<=I(j)) && (I(j)<=0.4)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0<=I(j))&& (I(j)<=0.2)
A(j)=I(j);
plot(A,'b-');
end
end

Malar Vizhi
Malar Vizhi el 14 de Ag. de 2022
If i give plot outside i got the output as same as signal
[x,fs] = audioread("sa.wav");
%end
si = 0.020;Fsi=si*fs;t=(0:1/Fsi);
frames=framing(x,fs,Fsi);
[r,c] = size(frames);
signal = zeros(size(0));
for i = 1:r
signal(i) = sum(frames(i,:).^2);
end
%
% plot(signal,'bo');
A=zeros(1,length(signal));
B=zeros(1,length(signal));
C=zeros(1,length(signal));
D=zeros(1,length(signal));
sig = max(signal);
for j=1:length(signal)
I(j)=(signal(j)/sig);
if(0.9<=I(j)) && (I(j)<=1)
A(j)=I(j);
% plot(A,'b-');hold on
elseif(0.6<=I(j)) && (I(j)<=0.9)
A(j)=I(j);
%plot(A,'b-');hold on
elseif(0.4<I(j)) && (I(j)<=0.6)
A(j)=I(j);
% plot(A,'b-');hold on
elseif(0.2<=I(j)) && (I(j)<=0.4)
A(j)=I(j);
% plot(A,'b-');hold on
elseif(0<=I(j))&& (I(j)<=0.2)
A(j)=I(j);
end
plot(A,'b-');
end
  1 comentario
Torsten
Torsten el 14 de Ag. de 2022
Yes, A is the signal, normalized to 1.
What else do you expect for the plot if you set
A = signal/max(signal)
(because this is what you do) ?

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Malar Vizhi
Malar Vizhi el 16 de Ag. de 2022
Actually this is like energy detector.I want compare highest amplitude with each amplitude of signal and seperate it into region of highest and lowest. Now the plot should differentiate these regions.
  2 comentarios
Torsten
Torsten el 16 de Ag. de 2022
Editada: Torsten el 16 de Ag. de 2022
Then you must plot something different from signal/max(signal) as you do.
Maybe a frequency distribution - I don't know:
A = signal/max(signal);
I = zeros(1,10);
for i = 1:10
I(i) = sum(A>=(i-1)/10 & A<i/10);
end
plot(1:10,I/numel(A))
Malar Vizhi
Malar Vizhi el 16 de Ag. de 2022

Thanks a lot.I will try it

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