count number of occurance

Hi, This is my first code in my life and I am somehow stuck.

Rolling two dice 100 times. sum of the two dice for each roll. The sum will be numbers between x= (2,3,4,5,6,7,8,9,10,11,12)

Then find how many occurance of the sum is qual to x.

the output would be like this:

x= (2,3,4,5,6,7,8,9,10,11,12)

y= (5,1,4,8,7,4,2,2,4,8,3)

here is my trial :

r1 = randi([1 6],1,100)

r2 = randi([1 6],1,100)

DiceSum=r1+r2

x = [2 3 4 5 6 7 8 9 10 11 12];

Then I stuck

[Walter Roberson]

When they say that you need to roll two dice 100 times and that you must use a for loop, then you are not permitted to instead roll 100 dice at a time and then another 100 dice at a time. You must roll two dice, process the result, roll another 2 dice, process, and so on.

[James Tursa]

What is the exact wording of the assignment?

[Bruno Luong]

"the output would be like this:"

x= (2,3,4,5,6,7,8,9,10,11,12)
y= (5,1,4,8,7,4,2,2,4,8,3)

If y is the occurance count to me the above numbers are very very unlikely. It adds up to 48 ad not 100!

If you tell this issue to your professor, you'll get the best (or the worst) grade.

Answer 1

[Image Analyst]

Rather than

r1 = randi([1 6],1,100);
r2 = randi([1 6],1,100);
DiceSum=r1+r2;

to get just one roll, I'd use randi to get all 100 rolls in just one call to randi, like this:

numRolls = 100;
numDice = 2;
rollResults = randi([1, 6], numRolls, numDice)

rollResults = 100×2

3 5 5 2 6 5 3 2 4 4 4 5 4 5 5 3 1 1 5 1

DiceSum = sum(rollResults, 2)

DiceSum = 100×1

8 7 11 5 8 9 9 8 2 6

% All done.  Now just some fancy plotting stuff.
histogram(DiceSum);
grid on;
caption = sprintf('Results of %d rolls of %d dice', numRolls, numDice);
title(caption);
ylabel('Count')
xlabel('2-Roll Sum')

[Me]

thanks alot. That is really help