Fill up submatrix along third dimension with two dimensional matrix

Given a p by p by N array, e.g. p=3 and N=4,

x = NaN(3,3,4);

I can easily fill up the 1 by 1 by N submatrix given a "1 by 1 matrix"doing

x(1,1,:) = 1;

But what if I want to fill up the 2 by 2 by N submatrix like this

x(1:2,1:2,:) = [1 2; 3 4];

This does not work.

How could I do it elegantly?

Answer 1

[Bruno Luong]

x(1:2,1:2,:) = repmat( [1 2; 3 4], 1, 1, size(x,3));

I would love to have MATLAB indexing to behave with auto expansion, but probably many users would be unhappy and complain because of coding error becoming silence.

Answer 2

[Torsten]

x = NaN(3,3,4);
x(1:2,1:2,:) = repmat([1 2; 3 4],1,1,4);
x

x = 
x(:,:,1) =

     1     2   NaN
     3     4   NaN
   NaN   NaN   NaN


x(:,:,2) =

     1     2   NaN
     3     4   NaN
   NaN   NaN   NaN


x(:,:,3) =

     1     2   NaN
     3     4   NaN
   NaN   NaN   NaN


x(:,:,4) =

     1     2   NaN
     3     4   NaN
   NaN   NaN   NaN